字符数组到浮点数的转换 [英] character array to floating point conversion

问题描述

我正在尝试转换输出缓冲区(字符数组)将下面的代码转换为浮点格式以供进一步计算.谁能告诉我怎么做.

I am trying to convert the output buffer(character array) of the code below to floating point format for further calculations. Can anybody tell me how to do it.

#include "usbtmc.h"
#include <errno.h>
#include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <stdlib.h>
#include <getopt.h>
#include <inttypes.h>
#include <sys/types.h>
#include <pthread.h>

int main() 
{

    int myfile;
    char buffer[4000];

    int actual;

    myfile=open("/dev/usbtmc1",O_RDWR);
    if(myfile>0)
    {
        system("echo MEAS:VOLT:AC?>/dev/usbtmc1");
        actual=read(myfile,buffer,4000);

        buffer[actual] = 0;
        printf("Response = 
 %s
",buffer);

        close(myfile);
    }


    return 0;
}

此代码的示例输出是

响应 =+1.29273072E-04

推荐答案

你可能有两种方法:

1. 使用 double atof(const char* str)

1. using double atof(const char* str)

float f;
f = (float)atof(buffer);
printf("%f",f); // here you can use f

使用 int sscanf( constchar * s, const char * 格式, ...)

using int sscanf( const char * s, const char * format, ...)

float f;
sscanf(buffer,"%f",&f);
printf("%f",f); // here you can use f

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