将无符号字符数组转换为浮点数组 [英] Casting an array of unsigned chars to an array of floats

问题描述

在c ++中将无符号char数组转换为float数组的最佳方法是什么？

What is the best way of converting a unsigned char array to a float array in c++?

我目前有如下的for循环

I presently have a for loop as follows

for (i=0 ;i< len; i++)
    float_buff[i]= (float) char_buff[i];

我还需要逆转该过程，即从无符号字符转换为浮点数（将浮点数转换为8bit）

I also need to reverse the procedure, i.e convert from unsigned char to float (float to 8bit conversion)

for (i=0 ;i< len; i++)
    char_buff[i]= (unsigned char) float_buff[i];

任何建议将不胜感激

谢谢

推荐答案

我认为最好的方法是使用函数对象：

I think the best way is to use a function object:

template <typename T> // T models Any
struct static_cast_func
{
  template <typename T1> // T1 models type statically convertible to T
  T operator()(const T1& x) const { return static_cast<T>(x); }
};

其后为：

std::transform(char_buff, char_buff + len, float_buff, static_cast_func<float>());
std::transform(float_buff, float_buff + len, char_buff, static_cast_func<unsigned char>());

这是最易读的，因为它说的是英语：将序列转换为其他使用静态强制类型输入。而且将来的转换可以在一行中完成。

This is the most readable because it says what is being done in English: transforming a sequence into a different type using static casting. And future casts can be done in one line.

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