将字符数组转换为浮点数? [英] Convert character array to float?

问题描述

我正在编写一个非常基本的命令行C ++应用程序，该应用程序在执行时会接受参数.

I'm writing a very basic command line C++ application that takes arguments on execution.

我今天才刚开始使用C ++，看来您只能将 char ** 作为参数的数据类型.我想将两个 float 用作参数(稍后再将它们添加在一起)，但是我似乎无法将字符数组转换为浮点型.

I just started C++ today, and it seems apparent that you can only take char** as the data type for arguments. I want to take two floats as parameters (to add them together later), but I can't seem to cast the character arrays as floats.

我尝试了 static_cast< float>(argv [0])和 stof(argv [0])来强制转换值，并且都给出了编译器错误(无法分别进行强制转换和未在范围内定义).

I have tried static_cast<float>(argv[0]) and stof(argv[0]) to cast the values, and both give compiler errors (unable to cast and not defined in scope, respectively).

如果正在回答任何问题，我正在使用 Code :: Blocks IDE .

I'm using the Code::Blocks IDE if that answers any questions.

我的代码:

#include <iostream>
#include <string>

/**
 * author: 2mac
 *
 */

using namespace std;

void derp();
float getSum(float num1, float num2);

int main(int argc, char** argv)
{
    float num1 = static_cast<float>(argv[0]);
    float num2 = static_cast<float>(argv[1]);

    if (argc != 0 || argc != 2)
        cout << "Usage: hello-world [args]\nargs: none OR <num1> <num2> to be added together" << endl;
    else
    {
        switch (argc)
        {
        case 0:
            derp();
            break;
        case 2:
            derp();
            cout << num1 << " + " << num2 << " equals " << getSum(num1,num2) << endl;
            break;
        }
    }
    return 0;
}

void derp()
{
    cout << "Hello, world!\n";
    cout << "It's time to lern some C++!" << endl;
}

float getSum(float num1, float num2)
{
    return num1 + num2;
}

推荐答案

使用此方法将您的输入转换为浮点数，

Using this to convert your input to float number,

double f1, f2;
if (argc == 2)
{
    f1 = atof (argv[0]);
    f2 = atof (argv[1]);
}

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