如何使用 DataContractJsonSerializer 序列化/反序列化存储在对象字段中的 DateTime? [英] How to serialize/deserialize a DateTime stored inside an object field using DataContractJsonSerializer?

问题描述

我使用以下类通过两个 ASP.NET 服务交换 JSON 数据:

I use the following class to exchange JSON data over two ASP.NET services :

[DataContract]
public class Filter
{
   [DataMember]
   public string Name {get; set;}

   [DataMember]
   public FilterOperator Operator {get; set;}

   [DataMember]
   public object Value {get; set;}    
}

问题来了:如果我在 Value 中设置了一个 DateTime，它将被反序列化为字符串:

Here is the problem : if I set a DateTime inside Value, it will be deserialized as string :

Value = "/Date(1476174483233+0200)/"

这可能是因为反序列化器在最初序列化时不知道值的类型:

This is probably because deserializer has no clue to know what was the type of the value when serialized initially :

JSON = {"Value":"/Date(1476174483233+0200)/"}

如 此处所述，DataContractJsonSerializer借助 __type 属性支持多态性.

As explained here, DataContractJsonSerializer supports polymorphism, with the help of the __type property.

我尝试在类的顶部添加 [KnownType(typeof(DateTime))] 属性，但没有帮助.

I have tried to add [KnownType(typeof(DateTime))] attribute on the top of the class but it does not help.

但是，如果我在 Value 属性中设置一个 Tuple (以及类上的相应 KnownType 属性)，它就可以工作(它正确反序列化的值):

However if I set a Tuple<DateTime> inside Value property (and the appropriate KnownType attribute on the class), it works (the value it deserialized properly) :

Value = {(10/11/2016 10:49:30 AM)}

在 JSON 内部，发出 __type

Inside JSON, __type is emited

JSON = {
     "Value": {
        "__type" : "TupleOfdateTime:#System",
        "m_Item1" : "/Date(1476175770028+0200)/"
     }
}

有没有办法强制 DataContractJsonSerializer 发出适当的信息以正确序列化/反序列化 DateTime (这意味着我在序列化后得到了一个 DateTime而不是字符串)?

Is there a way to force DataContractJsonSerializer to emit proper information to serialize/deserialize DateTime properly (which mean I got a DateTime after serialization instead of a string) ?

我尝试在 DataContractJsonSerializerSettings 中设置 EmitTypeInformation = EmitTypeInformation.Always 但没有帮助.

I have try to set EmitTypeInformation = EmitTypeInformation.Always in DataContractJsonSerializerSettings but it does not help.

推荐答案

问题是 DataContractJsonSerializer 只为对应的类型插入多态类型提示属性 "__type"到 JSON 对象 - 由 { 和 } 包围的一组无序的名称/值对.如果类型映射到其他任何东西(即 JSON 数组或原语)，则没有地方可以插入类型提示.此限制记录在 独立 JSON 序列化中:

The problem is that DataContractJsonSerializer only inserts a polymorphic type hint property "__type" for types that correspond to a JSON object - an unordered set of name/value pairs surrounded by { and }. If the type maps to anything else (i.e. a JSON array or primitive) then there is no place for a type hint to be inserted. This restriction is documented in Stand-Alone JSON Serialization:

类型提示仅适用于复杂类型

没有办法为非复杂类型发出类型提示.例如，如果操作具有 Object 返回类型但返回 Circle，则 JSON 表示可以如前所示，并保留类型信息.但是，如果返回 Uri，则 JSON 表示是一个字符串，并且用于表示 Uri 的字符串的事实将丢失.这不仅适用于原始类型，也适用于集合和数组.

There is no way to emit a type hint for non-complex types. For example, if an operation has an Object return type but returns a Circle, the JSON representation can be as shown earlier and the type information is preserved. However, if Uri is returned, the JSON representation is a string and the fact that the string used to represent a Uri is lost. This applies not only to primitive types but also to collections and arrays.

因此，您需要做的是修改您的 Filter 类，以序列化和反序列化其值的通用代理对象，该对象封装了值的类型信息，就像 Json.Net 的这个问题:

Thus what you will need to do is to modify your Filter class to serialized and deserialized a generic surrogate object for its value that encapsulates the value's type information, along the lines the one in this question for Json.Net:

[DataContract]
public class Filter
{
    [DataMember]
    public string Name { get; set; }

    [DataMember]
    public FilterOperator Operator { get; set; }

    [IgnoreDataMember]
    public object Value { get; set; }

    [DataMember]
    TypedSurrogate TypedValue
    {
        get
        {
            return TypedSurrogate.CreateSurrogate(Value);
        }
        set
        {
            if (value is TypedSurrogate)
                Value = ((TypedSurrogate)value).ObjectValue;
            else
                Value = value;
        }
    }
}

[DataContract]
// Include some well-known primitive types.  Other types can be included at higher levels
[KnownType(typeof(TypedSurrogate<string>))]
[KnownType(typeof(TypedSurrogate<bool>))]
[KnownType(typeof(TypedSurrogate<byte>))]
[KnownType(typeof(TypedSurrogate<sbyte>))]
[KnownType(typeof(TypedSurrogate<char>))]
[KnownType(typeof(TypedSurrogate<short>))]
[KnownType(typeof(TypedSurrogate<ushort>))]
[KnownType(typeof(TypedSurrogate<int>))]
[KnownType(typeof(TypedSurrogate<long>))]
[KnownType(typeof(TypedSurrogate<uint>))]
[KnownType(typeof(TypedSurrogate<ulong>))]
[KnownType(typeof(TypedSurrogate<float>))]
[KnownType(typeof(TypedSurrogate<double>))]
[KnownType(typeof(TypedSurrogate<decimal>))]
[KnownType(typeof(TypedSurrogate<DateTime>))]
[KnownType(typeof(TypedSurrogate<Uri>))]
[KnownType(typeof(TypedSurrogate<Guid>))]
[KnownType(typeof(TypedSurrogate<string[]>))]
public abstract class TypedSurrogate
{
    protected TypedSurrogate() { }

    [IgnoreDataMember]
    public abstract object ObjectValue { get; }

    public static TypedSurrogate CreateSurrogate<T>(T value)
    {
        if (value == null)
            return null;
        var type = value.GetType();
        if (type == typeof(T))
            return new TypedSurrogate<T>(value);
        // Return actual type of subclass
        return (TypedSurrogate)Activator.CreateInstance(typeof(TypedSurrogate<>).MakeGenericType(type), value);
    }
}

[DataContract]
public class TypedSurrogate<T> : TypedSurrogate
{
    public TypedSurrogate() : base() { }

    public TypedSurrogate(T value)
        : base()
    {
        this.Value = value;
    }

    public override object ObjectValue { get { return Value; } }

    [DataMember]
    public T Value { get; set; }
}

现在您的 JSON 将如下所示:

Now your JSON will look something like:

{
  "TypedValue": {
    "__type": "TypedSurrogateOfdateTime:#Question39973917",
    "Value": "/Date(1476244800000)/"
  }
}

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