使用另一个文件中的行范围替换单独文件中出现的字符串中的每2 n个 [英] Replace each 2 nth occurs from a string in separate files using line range from another file

问题描述

我有三个文件：

0.txte0-1.txt内容相同：

"#sun	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"#sun	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree(home_cool)	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree(home_cool)	",

和源文件1.txt如下：

(food, apple,)(bag, tortoise,)
(sky, cat,)(sun, sea,)
(car, shape)(milk, market,)
(man, shirt)(hair, life)
(dog, big)(bal, pink)

对于0.txt，我想将从home_cool开始出现的第2个替换为第1个1.txt行，但最多只能使用1.txt(然后sed -n '1,2p')的第二行，因此我的2.txt输出如下：

"#sun	",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))	",
"machine(shoes_shirt.shop)	",
"#sun	",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((food, apple,)(bag, tortoise,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((sky, cat,)(sun, sea,))	",

当在2.txt完成该过程时，我想将home_cool在0-1.txt出现的第2 n全部替换为第1 n行，使用1.txt的第三行(然后sed -n '3,5p')，这样我的3.txt输出如下：

"#sun	",
"car_snif = house.group_tree((car, shape)(milk, market,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((car, shape)(milk, market,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((man, shirt)(hair, life))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((man, shirt)(hair, life))	",
"machine(shoes_shirt.shop)	",
"#sun	",
"car_snif = house.group_tree((dog, big)(bal, pink))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((dog, big)(bal, pink))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((car, shape)(milk, market,))	",
"machine(shoes_shirt.shop)	",
"car_snif = house.group_tree((car, shape)(milk, market,))	",

使用下面的行，我可以将home_cool的替换分为两个步骤(第一步sed -n '1,2p'和第二步sed -n '3,5p')。但我想将第一步保存在2.txt中，将第二步保存在3.txt中：

awk 'NR==FNR {a[NR]=$0; n=NR; next}/home_cool/ { gsub("home_cool", a[int((++i-1)%(n*2)/2)+1])}1' <(cat 1.txt | tee >(sed -n '1,2p') >(sed -n '3,5p')) 0.txt >> 2.txt

所以我真正想要的是(下面的伪代码)：

awk 'NR==FNR {a[NR]=$0; n=NR; next}/home_cool/ { gsub("home_cool", a[int((++i-1)%(n*2)/2)+1])}1' <(cat 1.txt | tee >(sed -n '1,2p') >(sed -n '3,5p')) | "to sed -n '1,2p' make" 0.txt >> 2.txt | "to sed -n '3,5p' make" 0-1.txt >> 3.txt

如何通过维护命令行而不中断隔离的几个awk片段来完成此操作？

注意：也许问题的标题应该是：多个输入，相同的过程，不同的输出。

推荐答案

工作正常：

awk 
'FNR==1 {++f}
f==1 {a[i++]=$0}
f==2 {if ($0~/home_cool/) {gsub(/home_cool/, a[int(j++/2)%2]) }; print > "2.txt"}
f==3 {if ($0~/home_cool/) {gsub(/home_cool/, a[int(k++/2)%3 + 2]) }; print > "3.txt"}' 
    1.txt 0.txt 0-1.txt

硬编码"2.txt"和"3.txt"的替代方案包括：

• 使用-v outfile1=2.txt -v outfile2=2.txt
赋值的变量
• 替换为outfile，并使用此参数列表：1.txt outfile=2.txt 0.txt outfile=3.txt 0-1.txt
• 替换为ARGV[4]和ARGV[5]，添加f==4 {exit}行，使用参数列表：1.txt 0.txt 0-1.txt 2.txt 3.txt

注意事项：

• 如果给定的文件为空，则不会导致f递增，并相应地中断。在Gawk中，可以使用ENDFILE。查看此答案：How to get the filenumber that is being processing by an awk script?

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