在8086仿真打印十进制 [英] Print decimal in 8086 emulator

问题描述

我实现了两大整数乘法 EMU8086 与code如下：

I implemented the multiplication of two big integer in emu8086 with code as below :

; MULTIPLY N1 * N2 = RES
MULTIPLY PROC
    MOV BH, 0H        

    MOV CH, 0H
    MOV CL, L1; initial counter of first loop ( L1 -> length of N1 )
    DEC CX

    MUL_1:
        MOV COUNTER, CL ; store counter of first loop
        MOV CL, L2 ; initial counter of second loop ( L2 -> length of N2 )

        MUL_2:
            MOV BH, 0H
            MOV BL, COUNTER
            DEC BL
            MOV AL, N1[BX] ; get BX th byte of N1

            MOV BL, CL
            DEC BL

            MUL N2[BX] ; multiple N1 and N2 's bytes

            MOV BH, 0H
            MOV BL, COUNTER
            ADD BX, CX
            DEC BX

            ADD RES[BX], AL ; AL should be add into RES[loop1_counter + loop2_counter - 1]
            ADC RES[BX+1], AH; AH and carry should be add into RES[loop1_counter + loop2_counter ]
            ADC RES[BX+2], 0H; carry of above addition should be place here.
        LOOP MUL_2     

        MOV CL, COUNTER; retrieve loop 1 counter 
    LOOP MUL_1   

    RET ; end function 
MULTIPLY ENDP

所以，我想打印在小数模式，我知道如何打印导致十六进制：

So, i want to print it in Decimal Mode, i know how to print result in HexaDecimal :

PRINT_TABLE PROC
    MOV CX, 16D

    CASE:
        MOV BX, 16D
        SUB BX, CX

        MOV AL, RES[BX]

        CMP AL, 10D
        JB LBL1
        JAE LBL2


        LBL1:
            ADD AL, '0'
            JMP CONTINUE

        LBL2:
            ADD AL, 55D

        CONTINUE:

        MOV DL, AL
        MOV AH, 02H
        INT 21H        
    LOOP CASE
    RET
PRINT_TABLE ENDP

可能任何一个请帮我打印我的结果在10进制模式？

Could any one please help me to print my result in Decimal Mode ?

感谢您提前：）

推荐答案

我解决了我的问题，改变了我的code如下：

I solved my problem with changing my code as below :

NORMALIZE PROC
    MOV CH, 0H
    MOV CL, L1
    ADD CL, L2
    DEC CX

    NOMRALIZE_LOOP:
        MOV BX, CX
        DEC BX
        MOV AL, RES[BX]
        MOV AH, 1H
        MUL AH
        AAM            
        MOV RES[BX], AL
        ADD RES[BX-1], AH
    LOOP NOMRALIZE_LOOP
    RET
NORMALIZE ENDP

; MULTIPLY N1 * N2 = RES
MULTIPLY PROC
    MOV CH, 0H
    MOV CL, L1

    MOV AL, '0'

    MOV BH, 0H

    SUB_N1:
        MOV BL, CL 
        DEC BL
        SUB N1[BX], AL
    LOOP SUB_N1

    MOV CL, L2

    SUB_N2:
        MOV BL, CL
        DEC BL
        SUB N2[BX], AL
    LOOP SUB_N2

    MOV CH, 0H
    MOV CL, L1

    MUL_1:
        MOV COUNTER, CL
        MOV CL, L2  

        MUL_2:
            MOV BH, 0H
            MOV BL, COUNTER
            DEC BL
            MOV AL, N1[BX]

            MOV BL, CL
            DEC BL

            MUL N2[BX]

            AAM

            MOV BH, 0H
            MOV BL, COUNTER
            ADD BX, CX
            DEC BX
            DEC BX

            ADD RES[BX], AL
            ADC RES[BX-1], AH
            ADC RES[BX-2], 0H
        LOOP MUL_2     

        MOV CL, COUNTER
    LOOP MUL_1

    RET
MULTIPLY ENDP

我改变了乘法和存储号码与 AAM 功能。最后，我添加 NORMALIZE 函数结果转换成十进制。 ：）

I changed the multiplication and storing numbers with AAM function. At the end, i add NORMALIZE function to convert result to decimal. :)

希望其他人可以使用它：）

Hope others can use it :)

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