以十进制打印变量的地址 [英] Printing the addresses of variables in decimal

问题描述

我试图用十进制而不是十六进制打印数组元素的地址，但是它不起作用.下面是代码和输出示例.

I'm trying to print the addresses of the elments of an array in decimal instead of hexa but it doesn't work. Below is the code and output example.

#include <iostream>
#include <iomanip>
using namespace std;

void printarrandptr(int arr[], int size);
const int LEN = 5;

void main(){

    int arr[LEN] = { 15, 3, 14, 11, 14 };

    int *p[LEN];

    printarrandptr((int*)arr, LEN);
}

void printarrandptr(int arr[], int size){
    int i;

    for (i = 0; i < size; i++)
        cout << setw(9) << &arr[i] << setw(4) << arr[i] << endl;
    cout << endl;
}

输出示例:

 0098FDC8  15
 0098FDCC   3
 0098FDD0  14
 0098FDD4  11
 0098FDD8  14

推荐答案

ostream& operqator<<(ostream&, void*)的重载默认情况下使用十六进制格式.

There's a overload for ostream& operqator<<(ostream&, void*) that uses hex format by default.

cout << setw(9) << (long long)&arr[i] ...应该可以解决问题.

_{请不要讨论c风格的转换.}

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