在x86汇编操作数大小冲突？ [英] Operand size conflict in x86 Assembly?

问题描述

我是谁试图首次装配一个新手程序员。对不起提前如果这是一个令人难以置信的跛脚的问题。

I'm a novice programmer who is attempting assembly for the first time. Sorry in advance if this is an incredibly lame question.

我保存在EAX寄存器一个人物，但我需要将其移动到我的DL寄存器。当我尝试：MOV DL，EAX我得到一个错误C2443：操作数大小冲突。我知道EAX寄存器是32位，而DL是8位...我是对的东西？我该如何去解决这一点。

I have a character stored in the EAX register, but I need to move it to my DL register. When I try: mov dl, eax I get an error C2443: operand size conflict. I know that the eax register is 32 bit while the dl is 8 bit... am I on to something?? How do I go about solving this.

推荐答案

你想要的可能是：

movzx edx, al

这将复制A1至DL和零填充EDX的其余部分。这单指令相当于这两个指令：

This will copy al to dl and zero fill the rest of edx. This single instruction is equivalent these two instructions:

xor edx, edx 
mov dl, al

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