实现C＃方法返回任务＆LT; T＆GT;在F＃ [英] Implementing C# method returning Task<T> in F#

问题描述

我创建的F＃类型从该公开返回任务℃的方法的C＃类继承; T＆GT; 在C＃。我试图找出是什么了这样做，在F＃中的最佳方式。

I'm creating a type in F# that inherits from a C# class that exposes a method that returns Task<T> in C#. I'm trying to work out what'd be the best way to do that in F#

说我的C＃是这样的：

public class Foo {
    public TextWriter Out { get { return Console.Out; } }

    public virtual Task<SomeEnum> DoStuff() {
        return Task.FromResult(SomeEnum.Foo);
    } 
}

public enum SomeEnum {
    Foo,
    Bar
}

我继承F＃中该类型的第一遍看起来像这样：

My first pass of inheriting that type in F# looks like so:

type Bar() =
    inherits Foo()

    override this.DoStuff() =
        this.Out.WriteLineAsync("hey from F#") |> ignore

        System.Threading.Task.FromResult(SomeEnum.Bar)

但）它不觉得它实际上异步和b）只是感觉不-F＃。

But a) it doesn't feel like it's actually async and b) it just feels not-F#.

所以，我怎么会去继承富类，并实现了预计返回的 DoStuff 方法任务＆LT; T＆GT;

So how would I go about inheriting the Foo class and implement the DoStuff method that expects to return a Task<T>?

推荐答案

您可以使用 Async.StartAsTask

type Bar() =
    inherit Foo()
    override this.DoStuff() =
        async { return SomeEnum.Bar } |> Async.StartAsTask

Async.StartAsTask 需要异步＆LT; T＆GT; 作为输入，并返回一个任务＆LT ; T＆GT;

Async.StartAsTask takes Async<T> as input, and returns a Task<T>.

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