shell脚本：检查目录名和转换为小写 [英] shell script: check directory name and convert to lowercase

问题描述

我想我的bash脚本来检查其运行所在的目录的名称。是这样的：

I would like my bash script to check the name of the directory where it is run. Something like:

#!/bin/bash

path=eval 'pwd'

dirname=eval 'basename $path'

但它不工作：我得到

But it doesn't work: I get

./foo.sh: line 5: basename $path: command not found

我该如何解决？此外，一旦我得到目录名称包含正确的目录名称，我想将其转换为小写，对它进行测试。我能做到这一点使用awk在命令行上：

How can I fix it? Also, once I get dirname to contain the correct dirname, I'd like to convert it to lowercase, to test it. I'm able to do this on the command line with awk:

echo $dirname | awk '{print tolower($0)}'

但我如何获取返回值到一个变量？谢谢你在前进，

but how do I capture the return value into a variable? Thank you in advance,

此致

塞尔吉奥

推荐答案

为什么不使用：

#!/bin/bash

path=`pwd`
dirname=`basename $path | awk '{print tolower($0)}'`

或者，如果你想要做它作为一个单行：

Or if you want to do it as a one liner:

dirname=`pwd | xargs basename | awk '{print tolower($0)}'`

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