在bash脚本获取当前目录名（不完整路径） [英] Get current directory name (without full path) in Bash Script

问题描述

我将如何在bash脚本得到的只是当前工作目录名称，甚至更好，只是一个终端的命令。

How would I get just the current working directory name in a bash script, or even better, just a terminal command.

PWD 给出当前工作目录的完整路径，例如的/ opt / local / bin目录但我只想斌

pwd gives the full path of the current working directory, e.g. /opt/local/bin but I only want bin

推荐答案

无需基名，尤其是不需要一个子shell运行PWD（其中的增加了一个额外的，且价格昂贵，操作叉）;外壳可以做到这一点内部使用参数扩展：

No need for basename, and especially no need for a subshell running pwd (which adds an extra, and expensive, fork operation); the shell can do this internally using parameter expansion:

result=${PWD##*/}          # to assign to a variable

printf '%s\n' "${PWD##*/}" # to print to stdout
                           # ...more robust than echo for unusual names
                           #    (consider a directory named -e or -n)

printf '%q\n' "${PWD##*/}" # to print to stdout, quoted for use as shell input
                           # ...useful to make hidden characters readable.

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