捕获多线输出到一个bash变量 [英] Capturing multiple line output to a bash variable

问题描述

我有一个剧本的MyScript，输出如下：

I've got a script 'myscript' that outputs the following:

abc
def
ghi

在另一个脚本，我呼吁：

in another script, I call:

declare RESULT=$(./myscript)

和 $结果得到值

abc def ghi

有没有存储结果要么换行，或者用\\ n字符的方式，这样我就能把它输出回声-e '？

推荐答案

其实，结果中包含你想要的 - 证明：

Actually, RESULT contains what you want — to demonstrate:

echo "$RESULT"

什么告诉你是什么，你从中获取：

What you show is what you get from:

echo $RESULT

---

由于在评论中指出的，所不同的是：（1）变量的双引号的版本（回声$结果）preserves内部空间而（2）未加引号的版本（回声$结果） - 所有换行符，制表符，多个空格和 - 正是因为它是在变量psented重新$ p $的价值替换一个空格的一个或多个空格，制表符和换行符每个序列。因此（1）preserves输入变量的形状，而（2）创建了输出的一个潜在的非常长单行'单词'由单位（其中字是的非空白字符序列分离;不必有任何的话任何字母数字）

---

As noted in the comments, the difference is that (1) the double-quoted version of the variable (echo "$RESULT") preserves internal spacing of the value exactly as it is represented in the variable — newlines, tabs, multiple blanks and all — whereas (2) the unquoted version (echo $RESULT) replaces each sequence of one or more blanks, tabs and newlines with a single space. Thus (1) preserves the shape of the input variable, whereas (2) creates a potentially very long single line of output with 'words' separated by single spaces (where a 'word' is a sequence of non-whitespace characters; there needn't be any alphanumerics in any of the words).

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