简单的方法来洗牌在BASH外壳数组中的元素？ [英] Simple method to shuffle the elements of an array in BASH shell?

问题描述

我可以做到这一点在PHP，但我想在bash shell中工作。我需要一个数组，然后随机洗牌的内容并转储到 somefile.txt 。

I can do this in PHP but am trying to work within the BASH shell. I need to take an array and then randomly shuffle the contents and dump that to somefile.txt.

所以给定数组Heresmyarray，元素 A; B; C; d，E，F; 它会产生一个输出文件，输出。 TXT ，这将包含的元素 F;℃; b; A，E，D，

So given array Heresmyarray, of elements a;b;c;d;e;f; it would produce an output file, output.txt, which would contain elements f;c;b;a;e;d;

元素需要保留分号分隔符。我已经看到了一些的bash shell数组操作，但没有一种看上去甚至接近这个简单的概念。感谢您的任何帮助或建议！

The elements need to retain the semicolon delimiter. I've seen a number of bash shell array operations but nothing that seems even close to this simple concept. Thanks for any help or suggestions!

推荐答案

如果你只是想将它们放到一个文件（使用重定向>）

If you just want to put them into a file (use redirection > )

$ echo "a;b;c;d;e;f;" | sed -r 's/(.[^;]*;)/ \1 /g' | tr " " "\n" | shuf | tr -d "\n"
  d;a;e;f;b;c;

$ echo "a;b;c;d;e;f;" | sed -r 's/(.[^;]*;)/ \1 /g' | tr " " "\n" | shuf | tr -d "\n" > output.txt

如果你想放的物品在阵列

If you want to put the items in array

$ array=( $(echo "a;b;c;d;e;f;" | sed -r 's/(.[^;]*;)/ \1 /g' | tr " " "\n" | shuf | tr -d " " ) )
$ echo ${array[0]}
e;
$ echo ${array[1]}
d;
$ echo ${array[2]}
a;

如果你的数据有＆放大器; #abcde;

$ echo "a;&#abcde;c;d;e;f;" | sed -r 's/(.[^;]*;)/ \1 /g' | tr " " "\n" | shuf | tr -d "\n"
d;c;f;&#abcde;e;a;
$ echo "a;&#abcde;c;d;e;f;" | sed -r 's/(.[^;]*;)/ \1 /g' | tr " " "\n" | shuf | tr -d "\n"
&#abcde;f;a;c;d;e;

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