击：递归复制命名的文件，preserving文件夹结构 [英] Bash: Copy named files recursively, preserving folder structure

问题描述

我希望：

cp -R src/prog.js images/icon.jpg /tmp/package

将在目的地目录产生一个对称结构：

would yield a symmetrical structure in the destination dir:

/tmp
|
+-- package
    |
    +-- src
    |   |
    |   +-- prog.js
    |
    +-- images
        |
        +-- icon.jpg

但相反，这两个文件复制到/ tmp目录/包。平面复制。 （这是OSX）。

but instead, both of the files are copied into /tmp/package. A flat copy. (This is on OSX).

有一个简单的bash的功能，我可以用它来复制所有文件，包括通配符指定的文件（例如SRC / *。JS）到目标目录中应有的地位。好像有点为每个文件，运行的mkdir -p $（目录名称$文件）; CP$文件$（目录名称$文件），但也许一个命令。

Is there a simple bash function I can use to copy all files, including files specified by wildcard (e.g. src/*.js) into their rightful place within the destination directory. A bit like "for each file, run mkdir -p $(dirname "$file"); cp "$file" $(dirname "$file")", but perhaps a single command.

<一个href=\"http://www.linuxquestions.org/questions/linux-newbie-8/how-to-do-recursive-file-copy-of-directory-for-specific-files-199134/\">This是一个相关的线程，这表明这是不可能的。的作者的解决方案，对我来说并不那么有用，但因为我想简单地提供文件，通配符与否的名单，并有所有的人都复制到目标目录。 IIRC MS-DOS XCOPY做到这一点，但似乎没有类似的CP。

This is a relevant thread, which suggests it's not possible. The author's solution isn't so useful to me though, because I would like to simply provide a list of files, wildcard or not, and have all of them copied to the destination dir. IIRC MS-DOS xcopy does this, but there seems to be no equivalent for cp.

推荐答案

您是否尝试过使用--parents选项？我不知道，如果OS X支持，但在Linux上工作。

Have you tried using the --parents option? I don't know if OS X supports that, but that works on Linux.

cp --parents src/prog.js images/icon.jpg /tmp/package

如果没有在OS X上工作，尝试

If that doesn't work on OS X, try

rsync -R src/prog.js images/icon.jpg /tmp/package

为AIF建议。

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