如何使用bash做一些事来的每一个文件的目录中？ [英] How to do something to every file in a directory using bash?

问题描述

我开始用这样的：

command *

但是，当该目录为空它不工作;通配符*变成文字*字符。所以，我切换到这一点：

But it doesn't work when the directory is empty; the * wildcard becomes a literal "*" character. So I switched to this:

for i in *; do
   ...
done

这工作，但同样，如果没有该目录是空的。我使出使用LS：

which works, but again, not if the directory is empty. I resorted to using ls:

for i in `ls -A`

但当然，然后在他们的空间得到拆分的文件名。我试着套结了-Q开关：

but of course, then file names with spaces in them get split. I tried tacking on the -Q switch:

for i in `ls -AQ`

这将导致仍然被分割的名字，只在开头一个引号字符，名称的结束。我失去了一些东西在这里很明显，或者是这个难度比它它应该是什么？

which causes the names to still be split, only with a quote character at the beginning and ending of the name. Am I missing something obvious here, or is this harder than it ought it be?

推荐答案

假设你只想做一些事来的文件，简单的解决方案是测试如果$ i是一个文件：

Assuming you only want to do something to files, the simple solution is to test if $i is a file:

for i in * 
do
    if test -f "$i" 
    then
       echo "Doing somthing to $i"
    fi
done

您真的应该总是做这样的测试，因为你几乎肯定不希望把以同样的方式文件和目录。注意哪些美元，包含空格的文件名p $ pvent问题，围绕$ i的引号。

You should really always make such tests, because you almost certainly don't want to treat files and directories in the same way. Note the quotes around the "$i" which prevent problems with filenames containing spaces.

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