庆典发现​​，只有删除文件 - 参​​数顺序 [英] bash find, only delete files - order of arguments

问题描述

今天要说的是4月8日，我执行在bash下面。

Say today is April 8th and I execute the following in bash.

cd /tmp
mkdir hello
touch -d 2015-04-01 hello

然后，说我要删除/ tmp中年纪超过一天的所有文件，而不是目录和我执行此：

Then, say I want to delete all files in /tmp that are older than one day, but NOT directories and I execute this:

find /tmp -mtime +1 -delete -type f

为什么目录你好中删除，如果它不是一个文件？

Why is directory "hello" deleted if it's not a file?

谢谢！

推荐答案

find命令，以执行前pression。由于 -delete 为前型，型是从来没有达到过。尝试：

The find command executes the expression in order. Since -delete is before -type, -type is never reached. Try:

find /tmp -mtime +1 -type f -delete 

这篇关于庆典发现​​，只有删除文件 - 参​​数顺序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！