使用curl POST在bash脚本函数定义的变量 [英] Using curl POST with variables defined in bash script functions
问题描述
当我赞同我得到这个，它运行时，我将其输入端
When I echo I get this, which runs when I enter it into the terminal
curl -i \
-H "Accept: application/json" \
-H "Content-Type:application/json" \
-X POST --data '{"account":{"email":"akdgdtk@test.com","screenName":"akdgdtk","type":"NIKE","passwordSettings":{"password":"Starwars1","passwordConfirm":"Starwars1"}},"firstName":"Test","lastName":"User","middleName":"ObiWan","locale":"en_US","registrationSiteId":"520","receiveEmail":"false","dateOfBirth":"1984-12-25","mobileNumber":"9175555555","gender":"male","fuelActivationDate":"2010-10-22","postalCode":"10022","country":"US","city":"Beverton","state":"OR","bio":"This is a test user","jpFirstNameKana":"unsure","jpLastNameKana":"ofthis","height":"80","weight":"175","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}' https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx
但在bash脚本文件运行时，我得到这个错误
But when run in the bash script file, I get this error
curl: (6) Could not resolve host: application; nodename nor servname provided, or not known
curl: (6) Could not resolve host: is; nodename nor servname provided, or not known
curl: (6) Could not resolve host: a; nodename nor servname provided, or not known
curl: (6) Could not resolve host: test; nodename nor servname provided, or not known
curl: (3) [globbing] unmatched close brace/bracket at pos 158
这是code文件中的
curl -i \
-H '"'Accept: application/json'"' \
-H '"'Content-Type:application/json'"' \
-X POST --data "'"'{"account":{"email":"'$email'","screenName":"'$screenName'","type":"'$theType'","passwordSettings":{"password":"'$password'","passwordConfirm":"'$password'"}},"firstName":"'$firstName'","lastName":"'$lastName'","middleName":"'$middleName'","locale":"'$locale'","registrationSiteId":"'$registrationSiteId'","receiveEmail":"'$receiveEmail'","dateOfBirth":"'$dob'","mobileNumber":"'$mobileNumber'","gender":"'$gender'","fuelActivationDate":"'$fuelActivationDate'","postalCode":"'$postalCode'","country":"'$country'","city":"'$city'","state":"'$state'","bio":"'$bio'","jpFirstNameKana":"'$jpFirstNameKana'","jpLastNameKana":"'$jpLastNameKana'","height":"'$height'","weight":"'$weight'","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}'"'" "https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx"
我认为有一个问题，我的引号，但我跟他们打了很多，我已经得到了类似的错误。所有的变量在实际的脚本具有不同的功能所定义
I assume there's an issue with my quotation marks, but I've played with them a lot and I've gotten similar errors. All the variables are defined with different functions in the actual script
推荐答案
您并不需要通过封闭的自定义页眉卷曲引号。此外，您在数据的中间变量参数应该被引用。
You don't need to pass the quotes enclosing the custom headers to curl. Also, your variables in the middle of the data argument should be quoted.
试试这个code在你的脚本：
Try this code in your script:
curl -i \
-H "Accept: application/json" \
-H "Content-Type:application/json" \
-X POST --data '{"account":{"email":"'"$email"'","screenName":"'"$screenName"'","type":"'"$theType"'","passwordSettings":{"password":"'"$password"'","passwordConfirm":"'"$password"'"}},"firstName":"'"$firstName"'","lastName":"'"$lastName"'","middleName":"'"$middleName"'","locale":"'"$locale"'","registrationSiteId":"'"$registrationSiteId"'","receiveEmail":"'"$receiveEmail"'","dateOfBirth":"'"$dob"'","mobileNumber":"'"$mobileNumber"'","gender":"'"$gender"'","fuelActivationDate":"'"$fuelActivationDate"'","postalCode":"'"$postalCode"'","country":"'"$country"'","city":"'"$city"'","state":"'"$state"'","bio":"'"$bio"'","jpFirstNameKana":"'"$jpFirstNameKana"'","jpLastNameKana":"'"$jpLastNameKana"'","height":"'"$height"'","weight":"'"$weight"'","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}' "https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx"
在 -H 参数的双引号（如 -H富巴）告诉bash保持里面有什么作为一个参数（即使它包含空格）。
The double quotes in the -H arguments (as in -H "foo bar") tell bash to keep what's inside as a single argument (even if it contains spaces).
在单引号 - 数据参数（如 - 数据'富巴）做同样的，除非他们通过所有文字逐字（包括双引号字符和美元符号）。
The single quotes in the --data argument (as in --data 'foo bar') do the same, except they pass all text verbatim (including double quote characters and the dollar sign).
要在一个单一的引用文本的中间插入一个变量，你必须结束单引号，然后用双引号括可变串联，并重新打开单引号继续文本： '富巴$变量'多富'。
To insert a variable in the middle of a single quoted text, you have to end the single quote, then concatenate with the double quoted variable, and re-open the single quote to continue the text: 'foo bar'"$variable"'more foo'.
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