我怎样才能传给我的Bash循环变量间的Perl preTER？ [英] How can I pass on my Bash loop variable to the Perl interpreter?

问题描述

我想在bash和Perl的组合来修改某些脚本。麻烦的是，Perl的认为 $指数是其自己的变量，这是从来没有定义的：

I'm trying to modify some scripts with a combination of Bash and Perl. The trouble is that Perl thinks that $index is its own variable, which is never defined:

for index in {1..25}; do
    perl -pi -e 's/\d+/$index/' cmd_$index.sh;
done

有没有一种方法，使 $指数 Perl的单行内穿的斗篷猛砸？

Is there a way to make $index wear its Bash cloak within the Perl one-liner?

推荐答案

挤压的出口指数; 在不要循环。请参阅 $ ENV {指数} 在Perl程序的主体

Squeeze an export index; in the do loop. Refer to $ENV{index} in the body of the Perl program.

另外：使用双引号... $指数...来shell变量插值到前pression，构成了Perl程序的主体。如果你想扩展这一行，注意正确的逃生Perl的前pressions，如 $ 的变量名，也许反斜杠，这样是除$ p $被Perl PTED，而不是shell。

Alternatively: Use the double quotes "… $index … " to interpolate the shell variable into the expression that makes up the body of the Perl program. In case you want to expand this one-liner, take care to properly escape Perl expressions, such as $ on variable names, and perhaps backslashes, so that are interpreted by Perl, not the shell.

这篇关于我怎样才能传给我的Bash循环变量间的Perl preTER？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！