我怎样才能逃避正斜杠在用户输入变量在bash? [英] How can I escape forward slashes in a user input variable in bash?
问题描述
我工作的一个脚本,以建立一个网站Statamic更有效。我遇到的问题是,可变我使用替换文件中的字符串已经转义正斜杠,是用户输入。我怎样才能确保 _site_url:http://statamic.com
将成为 _site_url:http://example.com
?
下code将工作只要没有斜杠present。
回声什么是你的网站的网址,不要忘了协议?!(如HTTP://)
阅读-e SITE_URL回声%s / _site_url:HTTP:\\ / \\ / statamic.com/_site_url:$ SITE_URL / G
W¯¯
q
|恩_config / settings.yaml
问题是在你的前
命令的分隔符。我们可以把任何东西,我们希望不是,我用 @
这里:
试着这样做:
SED -iS @ _site_url:http://statamic.com/_site_url:$ @ SITE_URL G_config / settings.yaml
或与前
命令:
回声什么是你的网站的网址,不要忘了协议?!(如HTTP://)
阅读-e SITE_URL回声%S @ _site_url:HTTP://statamic.com@_site_url:$ @ SITE_URL摹
W¯¯
q
|恩_config / settings.yaml
I'm working on a script to make setting up a Statamic site more efficient. The problem I'm running into is that the variable I'm using to replace a string in a file has unescaped forward slashes and is user input. How can I make sure that _site_url: http://statamic.com
will become _site_url: http://example.com
?
The code below will work as long as there are no forward slashes present.
echo "What's your site URL? Don't forget the protocol (ex. http://)!"
read -e SITE_URL
echo "%s/_site_url: http:\/\/statamic.com/_site_url: $SITE_URL/g
w
q
" | ex _config/settings.yaml
The problem is the delimiter in your ex
command. We can put anything we'd like instead, I use @
here :
Try doing this :
sed -i "s@_site_url: http://statamic.com/_site_url: $SITE_URL@g" _config/settings.yaml
Or with your ex
command :
echo "What's your site URL? Don't forget the protocol (ex. http://)!"
read -e SITE_URL
echo "%s@_site_url: http://statamic.com@_site_url: $SITE_URL@g
w
q
" | ex _config/settings.yaml
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