陷阱火灾后退出 [英] Exit after trap fires

问题描述

把这个剧本

#!/bin/sh

fd ()
{
  echo Hello world
  exit
}

trap fd EXIT INT

for g in {1..5}
do
  echo foo
  sleep 1
done

我想 FD 火一次，无论是从控制-C或脚本正常退出。然而，如果你按下Control-C将运行两次。我该如何解决这个问题？

I would like fd to fire once, either from Control-C or if the script exits normally. However if you hit Control-C it will run twice. How can I fix this?

推荐答案

千万级联陷阱。 退出127 将运行退出陷阱和出口code设置为127，这样你就可以说

Do cascading traps. exit 127 will run the EXIT trap and set the exit code to 127, so you can say

#!/bin/sh

fd () {
  echo Hello world
  # No explicit exit here!
}

trap fd EXIT
trap 'exit 127' INT

我记得我从其他人的脚本与各种变通奋力您的问题几年后学习这种。在那之后，我注意到，一些教程做解释这种技术。但它不是如明确记载Bash的手册页恕我直言。 （或者它是不是当我需要它也许有些事情没有在15年内改变... ...： - ）

I remember learning this from other people's scripts after struggling with various workarounds to your problem for several years. After that, I have noticed that some tutorials do explain this technique. But it is not documented clearly in e.g. the Bash manual page IMHO. (Or it wasn't when I needed it. Maybe some things don't change in 15 years ... :-)

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