shell脚本，在文件系统中去N个文件夹 [英] Shell Script that goes up N folders in the file system

问题描述

我刚刚发现的this非常有用的shell脚本在这里SO但遗憾的是它不工作在Mac OS X 10.5。

I just found this very usefull shell script here on SO but unfortunately it's not working on Mac OS X 10.5.

这是有问题的脚本（复制它的便利）：

This is the script in question(copied it for convenience):

#!/bin/bash
LIMIT=$1
P=$PWD
for ((i=1; i <= LIMIT; i++))
do
    P=$P/..
done
cd $P

我试图回声$ P 的尽头，它的返回了正确的道路，但仍 CD $ P 似乎并不奏效。

I tried to echo $P at the very end and it's returning the right path, but still cd $P doesn't seem to be working.

于是，我就手动输入 P =一些/路径和 CD $ P 终端和它的工作。

So I tried to manually enter P="some/path" and cd $P in the terminal and it worked.

我不知道为什么在同一命令中没有脚本工作。难道是一个安全的事情吗？

I don't get why the same command isn't working in the script. Could it be a security thing?

有什么建议？

推荐答案

我已经在Linux上同样的问题，其实，如果我的理解正确的是什么，我经过一番搜索发现，这是发生了什么：

I've had the same issue on Linux, actually, if I understood correctly what I've found after some searching, this is what happens:

该命令在子shell中推出，并且在子shell路径得到改变，你看不到变化，因为当脚本完成，然后再回到起始（父）的外壳。

The command is launched in a subshell, and in that subshell the path gets changed, you don't see the change because when the script finishes you get back to the starting (parent) shell.

我解决了这个通过把有用的脚本在我的.bashrc作为函数，像这样的：

I solved this by putting that useful script in my .bashrc as a function, like this:

up(){
    #code goes here
}

另一个选择是每次启动它的时间源脚本，但我preFER第一位的。

Another option is to source the script every time you launch it but I prefer the first one.

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