shell脚本：改变工作目录，并在文件夹名称空间 [英] Shell script : changing working dir and spaces in folder name

问题描述

我想打一个脚本，需要一个文件路径参数，和CD到它的文件夹中。
这里是我做了什么：

I want to make a script that takes a file path for argument, and cds into its folder. Here is what I made :

#!/bin/bash

#remove the file name, and change every space into \space
shorter=`echo "$1" | sed 's/\/[^\/]*$//' | sed 's/\ /\\\ /g'`

echo $shorter
cd $shorter

其实我有2个问题（我是一个相对的新手到shell脚本）：

I actually have 2 questions (I am a relative newbie to shell scripts) :

• 我如何才能让光盘老大难？我想把这个脚本到/ usr / bin，然后再从任何地方在文件系统中调用它。在脚本的回报，我想留在 $短文件夹中。基本上，如果PWD是在/ usr / bin中，我可以通过键入做到这一点。脚本/我的/路径而不是 ./脚本/我的/路径，但如果我在其他文件夹？

• How could I make the cd "persistent" ? I want to put this script into /usr/bin, and then call it from wherever in the filesystem. Upon return of the script, I want to stay in the $shorter folder. Basically, if pwd was /usr/bin, I could make it by typing . script /my/path instead of ./script /my/path, but what if I am in an other folder ?

第二个问题是棘手。每当有在给定参数的空间我的脚本失败。虽然 $短是我想要的东西（比如 /家庭/插孔/我\\文件夹/子文件夹），CD蒙山失败误差的/ usr / bin中/脚本：4号线：CD：/家庭/插孔/我的\\：没有这种类型的文件或文件夹。我想我已经尝试了一切，因此，使用像 CD'$短或 CD'$短'于事无补。我在想什么？

The second question is trickier. My script fails whenever there is a space in the given argument. Although $shorter is exactly what I want (for instance /home/jack/my\ folder/subfolder), cd fails whith the error /usr/bin/script : line 4 : cd: /home/jack/my\: no file or folder of this type. I think I have tried everything, using things like cd '$shorter' or cd "'"$shorter"'" doesn't help. What am I missing ??

非常感谢你的答案

推荐答案

在的.bashrc 添加以下行：

function shorter() { cd "${1%/*}"; }

• ％表示，从年底
删除小格局

• / * 是百通


• % means remove the smaller pattern from the end
• /* is the patern

然后在你的终端：

$ . ~/.bashrc   # to refresh your bash configuration
$ type shorter  # to check if your new function is available
shorter is a function
shorter () 
{ 
    cd "${1%/*}"
}
$ shorter ./your/directory/filename  # this will move to ./your/directory

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