重定向标准输出到不同的日志一个COPY来自同一bash脚本中的文件多次 [英] Redirect a COPY of stdout to different log files multiple times from within same bash script

问题描述

行之后效果很好，当我们要重定向标准输出到一个文件，并同时获得印在标准输出。

Following line works well when we want to redirect the stdout to a file, and also get printed on stdout.

exec > >(tee logfile-1.txt)

但是，如果我们希望在以后的标准输出重定向到另一个文件，比方说，

However, if we wish to later redirect the stdout to another file, say,

exec > >(tee logfile-2.txt)

所面临的问题是，产量仍不断得到重定向到第二个文件（日志文件-2.txt）沿着第一个文件（日志文件-的1.txt）。

the issue faced is that the output still keeps getting redirected to the first file (logfile-1.txt) along with the second file (logfile-2.txt).

是否有相同的bash脚本包含的发言，并输出是排他性的每个对应于这些命令的执行顺序

Is there a way that the same bash script contains both the statement, and the output be exclusive to each of the files corresponding to the order of execution of these commands?

请注意：
这个问题是在扩展到解决方案以问的问题<一href=\"http://stackoverflow.com/questions/3173131/redirect-copy-of-stdout-to-log-file-from-within-bash-script-itself\">here.

推荐答案

我会做

{
    command1
    command2
} | tee logfile-1.txt

{
    command3
    command4
} | tee logfile-2.txt

此外，备份原来的文件描述符，第一：

Alternatively, backup the original filedescriptor, first:

exec 6<&1
exec > >(tee log1)
echo 1
echo 2
exec 1<&6 6<&-
exec > >(tee log2)
echo 3
echo 4

请参阅 http://www.linuxtopia.org/online_books/advanced_bash_scripting_guide/x13082.html 获取 EXEC

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