遍历数组的bash，替补数组名动态，这可能吗？ [英] Iterate over bash arrays, substitute array name dynamically, is this possible?

问题描述

我有过值的数组迭代，这样的事情（简单化为这一问题的目的）的脚本：

I have a script that iterates over an array of values, something like this (dumbed down for the purposes of this question) :

COUNTRIES=( ENGLAND SCOTLAND WALES )

for i in ${COUNTRIES[@]}
do                  
    echo "Country is $i "
done

我的问题是，是否有可能取代动态数组？例如，我希望能够在阵列中通过在运行时遍历。我试过以下，但我想我的语法可能是错误的。

My question is, is it possible to substitute the array dynamically? For example, I want to be able to pass in the array to iterate over at runtime. I've tried the following but I think my syntax might be wrong

COUNTRIES=( ENGLAND SCOTLAND WALES )
ANIMALS=( COW SHEEP DOG )

loopOverSomething()
{
    for i in ${$1[@]}
    do                  
        echo "value is $i "
    done
}

loopOverSomething $ANIMALS

我收到 22行：$ {$ 2 [@]}：替代不好

推荐答案

您可以使用bash的间接扩张的：

You can use bash's indirect expansion for this:

loopOverSomething()
{
    looparray="$1[@]"
    for i in "${!looparray}"
    do
        echo "value is $i"
    done
}

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