替代几行的文件，从另一个文件行 [英] substitute several lines in a file with lines from another file

问题描述

我有两个文件（A.TXT和B.txt）：

I have two files (A.txt and B.txt):

A.TXT：

  many lines of text
  marker
  A1  A2  A3
  A4  A5  A6
  ...
  ...     AN
  many line of text

B.txt：

  some text
  B1  B2  B3
  B4  B5  B6
  ...
  ...     BN

我要顶替的A1 - 在A.TXT AN块由B1 - BN从B.txt结果
请求的结果是：

I want to substitue the A1 - AN block in A.txt by B1 - BN from B.txt.
The requested result is:

  many lines of text
  marker
  B1  B2  B3
  B4  B5  B6
  ...
  ...     BN
  many line of text

我知道如何找块：

I know how to find the A block:

grep -n "marker" A.txt |cut -f1 -d:

我知道如何获得对B块：

I know how to get the B block:

sed -n '2,+6p' B.txt

我甚至可以编写脚本的东西，如：

I might even be able write a script with something like:

for ...
var=$(sed -n '2p' B.txt)
sed -i "34s/.*/$var/" A.txt

但我在寻找一些简单而优雅。

But I'm looking for something simple and elegant

推荐答案

• 您可以开始越来越B.txt的过滤类常：

• You can start getting the filtered constent of B.txt:

  sed -n '/B1/,$p' B.txt
  




• 然后就可以标记在A.TXT用的 研究命令：

• Then you can append it after marker in A.txt with the r command:

  sed "/marker/r"<(sed -n '/B1/,$p' B.txt) A.txt
  




• 然后你可以从 A1 直到 AN 在A.TXT删除：

• And then you can delete from A1 until AN in A.txt:

  sed "/A1/,/AN/d" A.txt
  




Altogheter

sed -e "/marker/r"<(sed -n '/B1/,$p' B.txt) -e "/A1/,/AN/d" A.txt

---

示例

$ sed -e "/marker/r"<(sed -n '/B1/,$p' B.txt) -e "/A1/,/AN/d" A.txt
  many lines of text
  marker
  B1  B2  B3
  B4  B5  B6
  ...
  ...     BN
  many line of text

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