如何查找和替换，跳过含有特定字符行？ [英] How to find and replace, skipping lines containing a particular character?

问题描述

我使用 SED 查找和替换模式的第一次出现在文件中：

I am using sed to find and replace the first appearance of an pattern in a file:

sed -i "0,\#pattern#s##replacement#" ./file.txt

我怎么能告诉它跳过任何包含这些行 {。下面是一个简单的输入：

How can I tell it to skip any of those lines containing {. Here is a sample input:

This line does not have the item, so it is skipped.
This line has the pattern, but also has {, so it is skipped too.
This line has the pattern, and not the character, so it will be changed.

下面是输出示例：

This line does not have the item, so it is skipped.
This line has the pattern, but also has {, so it is skipped too.
This line has the replacement, and not the character, so it will be changed.

• 只有一个变化在整个文件的。


• 如果有图案的每一行还包含 {，那么不更改该文件的。


• Only one change is made in the entire file.
• If every line with the pattern also contains {, then no changes are made to the file.

如何使用 SED 来查找和替换项目的首次亮相，但跳过含有另一种模式的线，在这种情况下 {？

How can I use sed to find and replace the first appearance of an item, but skipping any lines that contain another pattern, in this case {?

推荐答案

这可能会为你工作（GNU SED）：

This might work for you (GNU sed):

sed '/{/b;/pattern/{s//replacement/;:a;n;ba}' file

跳过含有任何行 {上的第一个模式匹配，替换它替换然后打印其余线路的档案结尾。

Skips any lines containing { on matching the first pattern, substitutes it for the replacement then prints remaining lines to the end-of-file.

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