如何删除方括号里面和任何文字？ [英] How to remove square brackets and any text inside?

问题描述

我有一个包含在方括号内一些文本，例如文档：

I have a document containing some text inside square brackets, e.g.:

The fish [ate] the bird.
[This is some] text.
Here is a number [1001] and another [1201].

我要删除所有包含的平方布拉克和brakets，例如中的信息：

I need to delete all of the information contained inside the square brack and the brakets, e.g.:

The fish  the bird.
 text.
Here is a number  and another .

• 我试过的sed -r的/ \\ [[+] \\] // G'file.txt的，但这并没有工作。


• I tried sed -r 's/\[[+]\]//g' file.txt, but this did not work.

我如何在模式中删除任何 [＆LT;什么＆GT;]

How can I delete anything in the pattern [<anything>]?

推荐答案

试试这个sed的行：

sed 's/\[[^]]*\]//g' 

例如：

kent$  echo "The fish [ate] the bird.
[This is some] text.
Here is a number [1001] and another [1201]."|sed 's/\[[^]]*\]//g' 
The fish  the bird.
 text.
Here is a number  and another .

说明：

正则表达式实际上是简单的：

the regex is actually straightforward:

\[     #match [
[^]]*  #match any non "]" chars
\]     #match ]

因此​​它是

匹配的字符串，从 [那么所有的字符，但] 和结束]

match string, starting with [ then all chars but ] and ending with ]

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