包含字符串读线（击） [英] Read line containing String (Bash)

问题描述

我有一个文件，它是这样的：

I have a file, and its something like this:

Device: name1
random text
Device: name2
random text
Device: name3
random text

我有一个变量：MainComputer

I have a variable: MainComputer

我想获得（每个名字，我有一个像40名）什么：

What I want to get (for each name, i have like 40 names):

   MainComputer -> name1
   MainComputer -> name2
   MainComputer -> name3

我有什么：

var="MainComputer"   
var1=$(awk '/Device/ {print $3}' file)
echo "$var -> $var1"

这不仅赋予了箭头 - >和链接的第一个变量，我希望他们为其他40个变量...

This only gives the arrow "->" and the link for the first variable, I want them for the other 40 variables...

不管怎样，谢谢！

推荐答案

让我present您 AWK ：

Let me present you awk:

$ awk '/Device/ {print $2}' file
name1
name2
name3

这对打印包含行设备第二个字段。如果您要检查，他们开始与设备，可以使用 ^设备：

This prints the second field on the lines containing Device. If you want to check that they start with Device, you can use ^Device:.

为了让你在编辑的问题提的输出，使用：

To get the output you mention in your edited question, use this:

$ awk -v var="MainComputer" '/Device/ {print var, "->", $2}' a
MainComputer -> name1
MainComputer -> name2
MainComputer -> name3

它通过 -v 提供变量名，然后打印就行了。

It provides the variable name through -v and then prints the line.

找到有关你的脚本一些评论：

Find some comments regarding your script:

file="/scripts/file.txt"
while read -r line
do
     if [$variable="Device"]; then # where does $variable come from? also, if condition needs tuning
     device='echo "$line"' #to run a command you need `var=$(command)`
echo $device #this should be enough
fi
done <file.txt #why file.txt if you already stored it in $file?

字符串相等来看看 [$变量 =设备]] 应该是语法（或类似）。

Check bash string equality to see how [[ "$variable" = "Device" ]] should be the syntax (or similar).

另外，你可以说同时读取-r名称值，使 $值将从第二包含价值上。

Also, you could say while read -r name value, so that $value would contain from the 2nd value on.

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