击：用数字字符串进行排序 [英] bash: sorting strings with numbers

问题描述

我经常要在它们与数字的字符串进行排序，以便，例如排序时 abc_2，abc_1，abc_10 的结果是 abc_1，abc_2，abc_10 。每样的机制我见过各种各样的 abc_1，abc_10，abc_2 ，也就是从左边的字符的字符。

I've often wanted to sort strings with numbers in them so that, when sorting e.g. abc_2, abc_1, abc_10 the result is abc_1, abc_2, abc_10. Every sort mechanism I've seen sorts as abc_1, abc_10, abc_2, that is character by character from the left.

有没有排序，得到我想要的结果，任何有效的方法？看着每个字符，确定它是一个数字，建立一个子参与后续数字的和排序的想法，作为一个数字是太骇人在庆典来考虑。

Is there any efficient way to sort to get the result I want? The idea of looking at every character, determining if it's a numeral, building a substring out of subsequent numerals and sorting on that as a number is too appalling to contemplate in bash.

没有胡子的* nix大师落实的替代版本排序与 - sensible_numerical 选项

Has no bearded *nix guru implemented an alternative version of sort with a --sensible_numerical option?

推荐答案

执行此

sort -t _ -k 2 -g data.file

• -t分隔符


• -k键/列


• -g一般数字排序



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