二进制sed替换 [英] binary sed replacement

问题描述

我试图做一个二进制文件 SED 更换然而，我开始相信这是不可能的。从本质上讲就是我想要做的是类似以下内容：

  SED -biS / \\（\\ XFF \\ xD8 [[：xdigit：]] \\ {1，\\} \\ XFF \\ xD9 \\）/ \\ 1 /文件。 JPG
 

我要实现的逻辑是：通过一个二进制文件，直到十六进制code FFD8 ，请继续阅读直到 FFD9 ，只救什么是他们（在丢弃垃圾之前和之后，但包括 FFD8 和 FFD9 作为文件的保存部分）

有没有做到这一点的好办法？即使不使用 SED ？

编辑：我只是玩了一圈，发现这样做IMO最彻底的方法。我知道这grep的声明将采取行动贪婪。

  hexdump都-ve1/1％.2x'dirty.jpg | grep的-o。FFD8 * ffd9| XXD -r -p＆GT; clean.jpg
 




解决方案

BBE 是一个sed的二进制文件 ，并应努力更有效地比hexdumping /重建大型二进制文件。

I was attempting to do a sed replacement in a binary file however I am beginning to believe that is not possible. Essentially what I wanted to do was similar to the following:

sed -bi "s/\(\xFF\xD8[[:xdigit:]]\{1,\}\xFF\xD9\)/\1/" file.jpg

The logic I wish to achieve is: scan through a binary file until the hex code FFD8, continue reading until FFD9, and only save what was between them (discards the junk before and after, but include FFD8 and FFD9 as the saved part of the file)

Is there a good way to do this? Even if not using sed?

EDIT: I just was playing around and found the cleanest way to do it IMO. I am aware that this grep statement will act greedy.

hexdump -ve '1/1 "%.2x"' dirty.jpg | grep -o "ffd8.*ffd9" | xxd -r -p > clean.jpg

解决方案

bbe is a "sed for binary files", and should work more efficiently for large binary files than hexdumping/reconstructing.

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