直接升压序列化字符数组 [英] Direct boost serialization to char array

问题描述

升压序列化的文档的断言，这样序列化/反序列化项目使用与底层结构的流二进制/文本存档。如果我wan't使用序列化的数据作为一个的std :: string这工作得很好，但我的本意是将其直接转换为char *缓冲区。我怎样才能做到这一点，而无需创建一个临时字符串？

解决了！对于那些想要一个例子中的：

 字符缓冲区[4096];提高::输入输出流:: basic_array_sink＆LT;＆烧焦GT; SR（缓冲，BUFFER_SIZE）;
提高::输入输出流::流＆LT;提高::输入输出流:: basic_array_sink＆LT;＆烧焦GT; ＆GT;源（SR）;提高::档案:: binary_oarchive OA（源）;OA＆LT;＆LT; serializable_object;
 

解决方案

IIUC，你想写信给固定大小的preallocated阵列。

您可以使用<一个href=\"http://www.boost.org/doc/libs/1_43_0/libs/iostreams/doc/index.html?path=4.2.1.3\">boost::iostreams::array_sink （包裹着<一个href=\"http://www.boost.org/doc/libs/1_43_0/libs/iostreams/doc/index.html?page=http://www.boost.org/doc/libs/1_43_0/libs/iostreams/doc/guide/generic_streams.html%23stream\">stream给它一个的std :: ostream的接口）为。

Boost serialization doc's assert that the way to serialize/deserialize items is using a binary/text archive with a stream on the underlying structure. This works fine if I wan't to use the serialized data as an std::string, but my intention is to convert it directly to a char* buffer. How can I achieve this without creating a temporary string?

Solved! For the ones that wanted a example:

char buffer[4096];

boost::iostreams::basic_array_sink<char> sr(buffer, buffer_size);  
boost::iostreams::stream< boost::iostreams::basic_array_sink<char> > source(sr);

boost::archive::binary_oarchive oa(source);

oa << serializable_object; 

解决方案

IIUC, you would like to write to a preallocated array of fixed size.

You could use a boost::iostreams::array_sink (wrapped with stream to give it an std::ostream interface) for that.

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