NULL指针与升压:: shared_ptr的? [英] NULL pointer with boost::shared_ptr?

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问题描述

什么是等同于以下内容:

 的std ::矢量<符* GT; VEC;
vec.push_back(NULL);

的boost :: shared_ptr的打交道时

?它是下列code?

 的std ::矢量<提高:: shared_ptr的<富> > VEC;
vec.push_back(提高:: shared_ptr的<富>());

请注意:我可能推回很多此类对象。我要声明一个全局静态 nullPtr 对象的地方?要构成,即仅他们中的一个将具有

 的boost :: shared_ptr的<富> nullPtr;


解决方案

您的建议(调用的shared_ptr< T> 不带参数的构造函数)是正确的。 (呼叫值为0相当于构造函数)。我不认为这将是比任何调用速度较慢 vec.push_back()以pre-现有的的shared_ptr< T> ,因为结构在两种情况下都需要(无论是直接施工或副本施工)

但如果你想更好的语法,你可以尝试以下code:

 类{
上市:
    模板< typename的T>
    运营商的shared_ptr< T>(){返回的shared_ptr< T>(); }
} nullPtr;

这声明了一个全局对象 nullPtr ,使下面自然的语法:

 的shared_ptr< INT>圆周率(新INT(42));
shared_ptr的< SomeArbitraryType> PSAT(新SomeArbitraryType(foonly));...PI = nullPtr;
PSAT = nullPtr;

请注意,如果你使用这个在多个翻译单元(源文件),你需要给一个类名(例如 _shared_null_ptr_type ),移动的定义在 nullPtr 对象到一个单独的.cpp文件,并添加的extern 的声明在头文件所在的类定义。

What's the equivalent to the following:

std::vector<Foo*> vec;
vec.push_back(NULL);

when dealing with boost::shared_ptr? Is it the following code?

std::vector< boost::shared_ptr<Foo> > vec;
vec.push_back(boost::shared_ptr<Foo>());

Note: I may push back a lot of such objects. Should I declare a global static nullPtr object somewhere? That way only one of them would have to be constructed:

boost::shared_ptr<Foo> nullPtr;

解决方案

Your suggestion (calling the shared_ptr<T> constructor with no argument) is correct. (Calling the constructor with the value 0 is equivalent.) I don't think that this would be any slower than calling vec.push_back() with a pre-existing shared_ptr<T>, since construction is required in both cases (either direct construction or copy-construction).

But if you want "nicer" syntax, you could try the following code:

class {
public:
    template<typename T>
    operator shared_ptr<T>() { return shared_ptr<T>(); }
} nullPtr;

This declares a single global object nullPtr, which enables the following natural syntax:

shared_ptr<int> pi(new int(42));
shared_ptr<SomeArbitraryType> psat(new SomeArbitraryType("foonly"));

...

pi = nullPtr;
psat = nullPtr;

Note that if you use this in multiple translation units (source files), you'll need to give the class a name (e.g. _shared_null_ptr_type), move the definition of the nullPtr object to a separate .cpp file, and add extern declarations in the header file where the class is defined.

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