升压线程问题 [英] Boost thread questions

问题描述

我试图做如下

class a{
public:
  void Start();
  void Tick();
  bool IsTimeOut;
};

void a::Start()
{
  boost::thread thread1(boost::bind(&a::Tick,this));
}
void a::Tick()
{
  while(!IsTimeOut)
  {
    boost::this_thread::sleep(boost::posix_time::millisec(1000));
  }
}

我的环境是VS2005和Win7。

My environment is vs2005 and win7.

不过，我总是得到访问冲突调试。

However, I always got the access violation in the debug.

推荐答案

这是访问冲突在这种情况下，就表示这个线程运行超出了 A 对象的生命周期

An access violation in this case would indicate that the thread is running beyond the lifetime of the a object.

IsTimeOut 需要要么是原子或互斥保护的，如果它被另一个线程写的，否则你的程序可能无法正常工作，但这不应该引起访问冲突。

IsTimeOut needs to either be atomic or protected by a mutex if it is written by another thread, otherwise your program might not work correctly, but this shouldn't cause the access violation.

您立即对象销毁的boost ::线程，从而分离线程，所以你没有等待它完成的方式。我建议存储线程对象为 A 的成员变量，无论是在析构函数与它加入 A 或与螺纹连接提供一个明确的的wait（）成员函数。

You are destroying the boost::thread object immediately, and thus detaching the thread, so you have no way of waiting for it to finish. I would suggest storing the thread object as a member variable of a, and either joining with it in the destructor of a or providing an explicit wait() member function that joins with the thread.

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