的Visual Studio 2012的错误C2039:'序列化':是不是成员'的std :: shared_ptr的&LT;&_Ty GT;' [英] Visual Studio 2012 error C2039: 'serialize' : is not a member of 'std::shared_ptr<_Ty>'
问题描述
我坚持这个问题,而我编译的静态类库。
我知道,升压不正式支持VS2012但由于这是我目前的开发环境,我真的可以使用一些建议。
我一直在寻找周围,但没有迄今已帮助了我。
样code:
foo.h中:
的#includeFooImpl.h
#包括LT&;升压/系列化/ serialization.hpp&GT;
#包括LT&;升压/系列化/ shared_ptr.hpp&GT;
#包括LT&;升压/存档/ text_iarchive.hpp&GT;
#包括LT&;升压/存档/ text_oarchive.hpp&GT;Foo类
{
上市:
美孚(void):在平普尔(性病:: make_shared&LT; FooImpl&GT;()){}
//类似的构造遵循 //一些get方法在这里
私人的:
的std :: shared_ptr的&LT; FooImpl&GT;平普尔; 友元类的boost ::系列化::访问;
模板&LT; typename的归档和GT;
无效连载(归档和放大器; AR,const的无符号整型FILE_VERSION);
}
Foo.cpp中:
的#includestdafx.h中
的#includefoo.h中模板&LT;类归档和GT;
无效美孚::连载(归档和放大器; AR,const的无符号整型版)
{
AR&安培;平普尔;
}模板无效美孚::连载&LT;提高::档案:: text_iarchive&GT;(
提高::档案:: text_iarchive&安培; AR,
const的无符号整型FILE_VERSION
);
模板无效美孚::连载&LT;提高::档案:: text_oarchive的&GT;(
提高::档案:: text_oarchive的&安培; AR,
const的无符号整型FILE_VERSION
);
FooImpl.h:
的#include&LT;升压/系列化/ serialization.hpp&GT;
#包括LT&;升压/系列化/ string.hpp&GT;类FooImpl
{
上市:
FooImpl(无效);
//其他构造函数,get方法私人的:
//数据成员 - 无符号整型和放大器;的std :: wstring的 友元类的boost ::系列化::访问;
模板&LT; typename的归档和GT;
无效连载(归档和放大器; AR,const的无符号整型版);
};
FooImpl.cpp:
的#includestdafx.h中
#包括FooImpl.h//函数实现模板&LT; typename的归档和GT;
无效FooImpl ::连载(归档和放大器; AR,const的无符号整型版)
{
AR&安培; ID_;
AR&安培; code_;
}//后来添加的,系列化要求这些模板无效FooImpl ::连载&LT;提高::档案:: text_iarchive&GT;(
提高::档案:: text_iarchive&安培; AR,
const的无符号整型FILE_VERSION
);模板无效FooImpl ::连载&LT;提高::档案:: text_oarchive的&GT;(
提高::档案:: text_oarchive的&安培; AR,
const的无符号整型FILE_VERSION
);
您正试图序列化指针。要序列化的东西指针指向。最简单的方法是更换富&LT;&LT; PTR;
与富&LT;&LT; (* PTR);
围绕 * PTR
括号是没有必要,很多人会认为他们是笨拙的迹象。但是,如果你发现他们更清楚你,使用它们。
I am stuck with this problem while compiling my static class library.
I know that Boost doesn't officially support VS2012 but since this is my current development environment, I could really use some advice.
I have been searching around but nothing so far has helped me.
Sample code:
Foo.h:
#include "FooImpl.h"
#include <boost/serialization/serialization.hpp>
#include <boost/serialization/shared_ptr.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/archive/text_oarchive.hpp>
class Foo
{
public:
Foo(void) : pImpl(std::make_shared<FooImpl>()) {}
//similar constructors follow
//a few get methods here
private:
std::shared_ptr<FooImpl> pImpl;
friend class boost::serialization::access;
template <typename Archive>
void serialize(Archive & ar, const unsigned int file_version);
}
Foo.cpp:
#include "stdafx.h"
#include "Foo.h"
template<class Archive>
void Foo::serialize(Archive& ar, const unsigned int ver)
{
ar & pImpl;
}
template void Foo::serialize<boost::archive::text_iarchive>(
boost::archive::text_iarchive & ar,
const unsigned int file_version
);
template void Foo::serialize<boost::archive::text_oarchive>(
boost::archive::text_oarchive & ar,
const unsigned int file_version
);
FooImpl.h:
#include <boost/serialization/serialization.hpp>
#include <boost/serialization/string.hpp>
class FooImpl
{
public:
FooImpl(void);
//other constructors, get methods
private:
//data members - unsigned int & std::wstring
friend class boost::serialization::access;
template <typename Archive>
void serialize(Archive& ar, const unsigned int ver);
};
FooImpl.cpp:
#include "stdafx.h"
#include "FooImpl.h"
//function implementations
template <typename Archive>
void FooImpl::serialize(Archive& ar, const unsigned int ver)
{
ar & id_;
ar & code_;
}
//Later added, serialization requires these
template void FooImpl::serialize<boost::archive::text_iarchive>(
boost::archive::text_iarchive & ar,
const unsigned int file_version
);
template void FooImpl::serialize<boost::archive::text_oarchive>(
boost::archive::text_oarchive & ar,
const unsigned int file_version
);
You are trying to serialize pointers. You want to serialize the thing the pointer points to. The simplest way is to replace foo << ptr;
with foo << (*ptr);
.
The parentheses around *ptr
are not necessary and many would see them as a sign of clumsiness. But if you find they make things clearer for you, use them.
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