除法结果始终为零 [英] Division result is always zero

问题描述

我得到这个C $ C $℃。

I got this C code.

#include <stdio.h>

int main(void)
{
        int n, d, i;
        double t=0, k;
        scanf("%d %d", &n, &d);
        t = (1/100) * d;
        k = n / 3;
        printf("%.2lf\t%.2lf\n", t, k);
        return 0;
}

我想知道为什么我的变量T始终为零（在printf函数）？

I want to know why my variable 't' is always zero (in the printf function) ?

推荐答案

因为在这个前pression

because in this expression

t = (1/100) * d;

1和100是整数值，整数除法截断，所以这这是相同的，因为这

1 and 100 are integer values, integer division truncates, so this It's the same as this

t = (0) * d;

你需要做一个恒定的浮动这样

you need make that a float constant like this

t = (1.0/100.0) * d;

您可能还希望做同样与此

you may also want to do the same with this

k = n / 3.0;

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