scanf函数不会要求输入第二次 [英] scanf won't ask for input the second time

问题描述

#include "stdio.h"

int main(void)
{

     int order, nextp, N=3;
     char cont;
     nextp = 0;
     printf("\nShould we continue (y or n): ");
     scanf("%c", &cont);
     if (cont != 'y') return;
     for(; nextp < N; nextp++)
     {
        printf("Enter order number: ");
        scanf("%d", &order);
        printf("you have entered %d\n", order);
        printf("okay now continue with cont\n");


        printf("enter cont y or n: ");
        scanf("%c", &cont);
        if (cont != 'y')
        {
            printf("\nnot equal to y\n");
            break;
        }
        printf("after intepreting t[0]");
      }

   return 0;
}

输出看起来像这样

The output looks like this

Should we continue (y or n): y
Enter order number: 45
you have entered 45
okay now continue with cont
enter cont y or n: 
not equal to y

第二个输入被跳过。为什么呢？

The second input was skipped. Why?

推荐答案

，这种情况正在发生。
用

because of newline character already in stdin , this is happening. use

scanf(" %c", &cont); 

而不是

scanf("%c", &cont);

请注意％C前一个空格。

note one space before %c.

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