为什么我们需要投什么malloc的回报？ [英] Why do we need to cast what malloc returns?

问题描述

    int length = strlen(src);
    char *structSpace = malloc(sizeof(String) + length + 1);
    String *string = (String*) structSpace;    
    int *string = (int*) structSpace;

*我创建了一个名为字符串结构

*I created a struct called String

推荐答案

您没有。 无效* 将隐式转换，无论你在C.见需要还的为什么你会想要明确地避免铸造的malloc在C.回报@思南的答案C FAQ 进一步说明了为什么这已经不一致遵循。

You don't. void* will implicitly cast to whatever you need in C. See also the C FAQ on why you would want to explicitly avoid casting malloc's return in C. @Sinan's answer further illustrates why this has been followed inconsistently.

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