二维字符数组的动态内存 [英] dynamic memory for 2D char array

问题描述

我宣布一个数组
焦炭** ARR;
如何初始化二维字符数组的内存。

I have declared an array char **arr; How to initialize the memory for the 2D char array.

推荐答案

一种方法是做到以下几点：

One way is to do the following:

char **arr = (char**) calloc(num_elements, sizeof(char*));

for ( i = 0; i < num_elements; i++ )
{
    arr[i] = (char*) calloc(num_elements_sub, sizeof(char));
}

这是相当清楚这里发生了什么 - 首先，你初始化数组的指针，那么这个数组你分配一个字符数组中的每个指针

It's fairly clear what's happening here - firstly, you are initialising an array of pointers, then for each pointer in this array you are allocating an array of characters.

您可以在一个功能包装这件事。你需要释放（）他们来说，使用后，像这样的：

You could wrap this up in a function. You'll need to free() them too, after usage, like this:

for ( i = 0; i < num_elements; i++ )
{
    free(arr[i]);
}

free(arr);

我觉得这个做的事情和最简单的方式匹配你所需要的。

I think this the easiest way to do things and matches what you need.

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