用C比较的char []平等 [英] Compare equality of char[] in C

问题描述

我有两个变量：

 字符charTime [] =TIME;
烧焦BUF [] =SOMETHINGELSE;
 

我要检查，如果这两个都是平等的......使用 charTime == BUF 不起作用。

我应该怎么用了，有人可以解释为什么使用 == 不起作用？

请问这个动作是C和C ++不同？

解决方案

 字符charTime [] =TIME;烧焦BUF [] =SOMETHINGELSE;
 

C ++ 和 C （删除的std :: 为C）：

 布尔等于=（的std :: STRCMP（charTime，BUF）== 0）;
 

但是，真正的C ++方式：

 的std ::字符串charTime =TIME，BUF =SOMETHINGELSE;
布尔等于=（charTime == BUF）;
 

使用 == 不起作用，因为它试图地址比较每个阵列（显然​​，他们这样做不等于）的第一个字符。它不会比较两个阵列的内容。

I have two variables:

char charTime[] = "TIME";
char buf[] = "SOMETHINGELSE";

I want to check if these two are equal... using charTime == buf doesn't work.

What should I use, and can someone explain why using == doesn't work?

Would this action be different in C and C++?

解决方案

char charTime[] = "TIME"; char buf[] = "SOMETHINGELSE";

C++ and C (remove std:: for C):

bool equal = (std::strcmp(charTime, buf) == 0);

But the true C++ way:

std::string charTime = "TIME", buf = "SOMETHINGELSE";
bool equal = (charTime == buf);

Using == does not work because it tries to compare the addresses of the first character of each array (obviously, they do not equal). It won't compare the content of both arrays.

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