fopen（）函数返回NULL指针，但该文件存在绝对 [英] fopen() returning a NULL pointer, but the file definitely exists

问题描述

在code我有如下：

FILE *txt_file = fopen("data.txt", "r");
if (txt_file == NULL) {
    perror("Can't open file");
} 

返回的错误信息是：

The error message returned is:

无法打开文件：没有这样的文件或目录

Can't open file: No such file or directory

文件'的data.txt'在工作目录（它存在于包含我的.c和.h文件的目录），所以为什么fopen（）函数返回一个空指针？肯定是存在的。

The file 'data.txt' definitely exists in the working directory (it exists in the directory that contains my .c and .h files), so why is fopen() is returning a NULL pointer?

推荐答案

是否有可能的文件名是不是真的存在data.txt？

Is it possible that the filename is not really "data.txt"?

在Unix上，文件名是真正字节字符串不是字符串，它可以创建与对照文件，如在其名称中退格。我已经看到在过去的案件中，复制粘贴到终端的结果与平常的名字，但试图打开出现在目录列表中导致错误的文件名。

On Unix, filenames are really byte strings not character strings, and it is possible to create files with controls such as backspace in their names. I have seen cases in the past in which copy-pasting into terminals resulted in files with ordinary-looking names, but trying to open the filename that appears in a directory listing results in an error.

要肯定地告诉了真名是什么，你认为他们是一个方法：

One way to tell for sure that the filenames really are what you think they are:

$ python
>>> import os
>>> os.listdir('.')

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