如何将指针初始化到在C中的特定存储器地址++ [英] How to initialize a pointer to a specific memory address in C++

问题描述

可能重复：结果
  指向特定的固定地址

这个一个有趣的讨论开始<一href=\"http://stackoverflow.com/questions/3933263/questions-every-good-c-c-developer-should-be-able-to-answer/3933402#3933402\">here但没有人已经能够提供这样的C ++方式：

An interesting discussion about this started here but no one have been able to provide the C++ way of doing:

#include <stdio.h>

int main(void)
{
  int* address = (int *)0x604769; 
  printf("Memory address is: 0x%p\n", address);

  *address = 0xdead; 
  printf("Content of the address is: 0x%p\n", *address);

  return 0;
}

什么是用C做这样的事++最合适的方式？

What is the most appropriate way of doing such a thing in C++?

推荐答案

在C ++中，总是preFER reinter pret_cast 通过C-演员。它是如此丑陋的屁股，有人会立即发现的危险。

In C++, always prefer reinterpret_cast over a C-cast. It's so butt ugly that someone will immediately spot the danger.

例如：

int* ptr = reinterpret_cast<int*>(0x12345678);

这件事伤害了我的眼睛，我喜欢它。

That thing hurts my eyes, and I like it.

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