转换1位的bmp文件在C / C ++数组 [英] Converting 1-bit bmp file to array in C/C++
问题描述
我期待把可变高度/宽度的1位的bmp文件到一个简单的二维数组的0或1的值,我没有在code。与图像编辑的经验而且我发现大多数图书馆涉及到较高的比特深度比我需要什么。任何有关此帮助将是巨大的。
I'm looking to turn a 1-bit bmp file of variable height/width into a simple two-dimensional array with values of either 0 or 1. I don't have any experience with image editing in code and most libraries that I've found involve higher bit-depth than what I need. Any help regarding this would be great.
推荐答案
这里的code到读取单色.bmp文件
Here's the code to read a monochrome .bmp file
#include <stdio.h>
#include <string.h>
#include <malloc.h>
unsigned char *read_bmp(char *fname,int* _w, int* _h)
{
unsigned char head[54];
FILE *f = fopen(fname,"rb");
// BMP header is 54 bytes
fread(head, 1, 54, f);
int w = head[18] + ( ((int)head[19]) << 8) + ( ((int)head[20]) << 16) + ( ((int)head[21]) << 24);
int h = head[22] + ( ((int)head[23]) << 8) + ( ((int)head[24]) << 16) + ( ((int)head[25]) << 24);
// lines are aligned on 4-byte boundary
int lineSize = (w / 8 + (w / 8) % 4);
int fileSize = lineSize * h;
unsigned char *img = malloc(w * h), *data = malloc(fileSize);
// skip the header
fseek(f,54,SEEK_SET);
// skip palette - two rgb quads, 8 bytes
fseek(f, 8, SEEK_CUR);
// read data
fread(data,1,fileSize,f);
// decode bits
int i, j, k, rev_j;
for(j = 0, rev_j = h - 1; j < h ; j++, rev_j--) {
for(i = 0 ; i < w / 8; i++) {
int fpos = j * lineSize + i, pos = rev_j * w + i * 8;
for(k = 0 ; k < 8 ; k++)
img[pos + (7 - k)] = (data[fpos] >> k ) & 1;
}
}
free(data);
*_w = w; *_h = h;
return img;
}
int main()
{
int w, h, i, j;
unsigned char* img = read_bmp("test1.bmp", &w, &h);
for(j = 0 ; j < h ; j++)
{
for(i = 0 ; i < w ; i++)
printf("%c ", img[j * w + i] ? '0' : '1' );
printf("\n");
}
return 0;
}
这是纯C,所以没有指针铸造 - 而在C ++中使用它提防
It is plain C, so no pointer casting - beware while using it in C++.
最大的问题是,在.bmp文件的线是4字节对齐这是相当重要的单位的图像。因此,我们计算行大小为宽/ 8 +(宽/ 8)%4。每个字节包含8个像素,而不是一个,所以我们用K-基于循环。
The biggest problem is that the lines in .bmp files are 4-byte aligned which matters a lot with single-bit images. So we calculate the line size as "width / 8 + (width / 8) % 4". Each byte contains 8 pixels, not one, so we use the k-based loop.
我希望其他code是显而易见的 - 许多人已告知.BMP头和调色板数据(8字节,我们跳过)
I hope the other code is obvious - much has been told about .bmp header and pallete data (8 bytes which we skip).
期望的输出:
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0
0 0 0 0 0 0 1 1 1 1 0 0 1 1 0 0
0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 1 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 0 1 1 1 1 0 0 1 0 0 0
0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 1 1 1 1 1 0 0 0 0 1 0
0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0
0 0 0 1 0 1 1 1 1 1 0 0 0 0 0 0
0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0
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