为什么这个整数除法产生出0？ [英] Why does this integer division yield 0?

问题描述

有人能告诉我，为什么下面的code在标线输出 0 ？

看来仿佛一切都是正确的，但后来当我试图让附近它给我0每次最终结果。

 的#include＆LT;＆stdio.h中GT;诠释主（）{    //收集时间推移变量    INT帧率，totalLengthSecs;
    的printf（有多少帧每秒：）;
    scanf函数（％i的，＆安培;帧率）;
    的printf（ - ＆GT;％I帧的证实。帧率）;
    的printf（延时[秒]的\\ nDesired长：）;
    scanf函数（％i的，＆安培; totalLengthSecs）;
    的printf（ - 方式＆gt;％I秒证实，totalLengthSecs）;
    INT totalFrames =帧率* totalLengthSecs;
    的printf（\\ n您需要％I帧。totalFrames）;    //定时间隔计算    INT timeLapseInterval = totalLengthSecs / totalFrames;    的printf（\\ n \\ n％I，timeLapseInterval）; //＆LT;  - 这将打印0    返回0;
}
 

解决方案

在短期：整数除法截断

您需要以下内容：

 双timeLapseInterval =（双）totalLengthSecs /（双）totalFrames;
的printf（\\ ntimeLapseInterval：％F \\ N，timeLapseInterval）;
 

Could someone tell me why the following code is outputting 0 at the marked line?

It seems as if everything is correct but then when I try to get the result near the end it's giving me 0 each time.

#include <stdio.h>

int main() {

    // Gather time-lapse variables

    int frameRate, totalLengthSecs;
    printf("How many frames per second: ");
    scanf("%i", &frameRate);
    printf("--> %i frames confirmed.", frameRate);
    printf("\nDesired length of time-lapse [secs]: ");
    scanf("%i", &totalLengthSecs);
    printf("--> %i seconds confirmed.", totalLengthSecs);
    int totalFrames = frameRate * totalLengthSecs;
    printf("\nYou need %i frames.", totalFrames);

    // Time-lapse interval calculation

    int timeLapseInterval = totalLengthSecs / totalFrames;

    printf("\n\n%i", timeLapseInterval); // <-- this prints 0

    return 0;
}

解决方案

In short: Integer division truncates

You need the following:

double timeLapseInterval = (double) totalLengthSecs / (double)totalFrames;
printf("\ntimeLapseInterval : %f \n", timeLapseInterval);

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