C编程：'和;'在scanf函数阵列 [英] C programming: '&' with arrays in scanf
问题描述
我在我的节目一个警告，它说：
I got a warning in my program, and it says:
格式'％C'型预期'字符*'的说法，但参数2的类型'字符（*）[10] - [-Wformat]
下面是我的程序：
#include<stdio.h>
int main()
{
char array[10];
scanf("%10c", &array);
printf("%.10s", array);
return 0;
}
当我删除，警告消失'和;'从scanf函数。
我知道，这是一个数组，并且不需要与功放;.但是，不要他们有同样的效果？
我的意思是这两个'和;阵'和'阵'给它的第一个元素的地址，对不对？
如果是这样，这里有什么区别呢？
The warning disappears when I remove '&' from scanf. I know, it's an array and doesn't require &. But don't they have same effect? I mean both '&array' and 'array' give address of its first element, right? If so, what's the difference here?
我在这里阅读一些相关的问题，并用Google搜索了很多。
有人说，'和;阵'是一个指向字符数组，如果数组是一个数组，而数组本身就是一个字符指针。
据它说什么，因为我使用的是C，一个指向的字符数组应传递，我想。
IDK，我会很感激，如果有人介绍了如何％[宽度] c ++工程。
I read some related questions here, and googled a lot. It has been said that '&array' is a pointer to an array of characters if 'array' is an array while 'array' itself is a pointer to char. According to what it says, since I'm using %c, a pointer to an array of characters should be passed, I think. Idk, I would very greatful if someone explains how %[width]c works.
我也验证了所有'阵'，'和;阵'和'和;数组[0]'给它的第一个元素的地址。
下面是我所做的：
I also verified that all 'array', '&array' and '&array[0]' give address of its first element. Here's what I did:
int main()
{
char array[10];
puts("ADDRESS:");
printf(" %p \n %p \n %p", array, &array, &array[0]);
return 0;
}
如果他们都给予相同的地址，它为什么给人这样的警告？
这也适用于％S。
他们都在大多数窗口编译器做工精细，没有任何警告。
If they all give same address, why is it giving such warnings? It also works for %s. They all work fine in most of windows compiler, without any warnings.
由于我是Windows用户，我从来没有使用过的gcc编译器。而我在想什么是它只是不强制写＆安培;与函数指针。
你不一定必须写＆安培;与函数指针，我读
Since I'm a windows user, I never used gcc compiler before. And what I was thinking was it's just not mandatory to write & as with function pointers. You don't necessarily have to write & with function pointers, I read.
我越来越糊涂了，请帮我把它。
I'm getting more and more confused, please help me get it.
感谢您。
推荐答案
阵列和＆放大器;阵列这两个收益率一个指向同一个地址，但具有不同的类型。前者是在大多数情况下，以＆放等价;数组[0] ，一个的char * 你的情况。 ＆放大器;阵列，然而，这是数组本身，其类型的地址字符（*）[10] 在你的例子。
array and &array both yield a pointer to the same address, but with different types. The former is equivalent in most situations to &array[0], a char * in your case. &array, however, is the address of the array itself, which has type char (*)[10] in your example.
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