阅读文件的内容在C十六进制 [英] Read contents of a file as hex in C

问题描述

我有哪些具有保存为 hex.txt 的十六进制值的文件

I have a file with hex values saved as hex.txt which has

9d ff d5 3c 06 7c 0a

现在我需要将其转换为字符数组作为

Now I need to convert it to a character array as

unsigned char hex[] = {0x9d,0xff,0xd5,0x3c,0x06,0x7c,0x0a}

我该怎么办呢？

推荐答案

这code做工作!!!，而是要求我们初始化十六进制的大小与转换＃定义FILELEN 15

This code does the job !!!, but requires us to initialize the size of the hex to be converted with #define FILELEN 15

#include<stdio.h>

#define FILELEN 15

int ascii_to_hex(char c)
{
        int num = (int) c;
        if(num < 58 && num > 47)
        {
                return num - 48; 
        }
        if(num < 103 && num > 96)
        {
                return num - 87;
        }
        return num;
}

int main()
{
        FILE *fp = fopen("sample","r");
        unsigned char c1,c2;
        int i=0;
        unsigned char sum,final_hex[FILELEN/2];
        for(i=0;i<FILELEN/2;i++)
        {
                c1 = ascii_to_hex(fgetc(fp));
                c2 = ascii_to_hex(fgetc(fp));
                sum = c1<<4 | c2;
                final_hex[i] = sum;
                printf("%02x ",sum);
        }
        printf("\n");
}

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