C ++ cout十六进制格式 [英] C++ cout hex format

问题描述

我是一个c ++编码器，新到c ++。

i am a c coder, new to c++.

我尝试打印以下cout与奇怪的输出。对此行为的任何评论赞赏。

i try to print the following with cout with strange output. Any comment on this behaviour is appreciated.

#include<iostream>
using namespace std;

int main()
{
        unsigned char x = 0xff;

        cout << "Value of x  " << hex<<x<<"  hexadecimal"<<endl;

        printf(" Value of x %x by printf", x);
}

输出：

 Value of x  ÿ  hexadecimal
 Value of x ff by printf

推荐答案

，iostreams可能是一个痛苦与他们的操纵者。要做任何有趣的人类可读输出，你可能想看看boost ::格式，它带来printf的所有喜悦到类型安全输出的世界。

also, iostreams can be a pain with their 'manipulators'. To do anything interesting for human readable output, you might want to look at boost::format, which brings all the joys of printf to the world of typesafe output.

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