串联2矩阵 [英] concatenate 2 matrices
问题描述
我有一个矩阵动态分配,我想创造一个又一个这是第一个矩阵但旁边另一个副本。例如,我有矩阵:
11
22
我的新的矩阵将是:
1 1 1 1
2 2 2 2
我怎样才能将它们连接起来?这是我的code在C:
#包括LT&;&stdio.h中GT;
#包括LT&;&CONIO.H GT;
#包括LT&;&stdlib.h中GT;INT ** create_matrix(INT行,诠释山口)
{
INT **矩阵=的malloc(sizeof的为(int *)*行);
INT I;
对于(i = 0; I<排;我++)
{
矩阵[I] =的malloc(sizeof的(INT)* COL);
}
返回矩阵;
}无效matrix_input(INT **矩阵,诠释行,诠释山口)
{
INT I,J;
输出(输入矩阵的元素:\\ n);
对于(i = 0; I<排;我++)
{ 为(J = 0; J<西; J ++)
{
scanf函数(%d个,&安培;矩阵[I] [J]);
}
}
}INT ** extend_matrix(INT **矩阵,诠释行,诠释山口)
{
INT K,J;
INT I;
INT ** extend_matrix =的malloc(sizeof的为(int *)*行);
对于(K = 0; K<排排+; k ++)
{
extend_matrix [K] =的malloc(sizeof的(INT)* COL);
}
extend_matrix =矩阵;
extend_matrix =(INT **)的realloc(extend_matrix,(行+行)* sizeof的为(int *));
extend_matrix [J] =矩阵[J]。
对于(i = 0; I<排;我++)
{
extend_matrix [K] =矩阵[I];
}
}无效print_matrix(INT **矩阵,诠释行,诠释山口)
{
INT I,J;
对于(i = 0; I<排;我++)
{
为(J = 0; J<西; J ++)
{
的printf(%d个,矩阵[I] [J]);
}
的printf(\\ n);
}}无效print_extend_matrix(INT ** extend_matrix,诠释行,诠释山口)
{
INT K,J;
对于(K = 0; K<排排+; k ++)
{
为(J = 0; J<西; J ++)
{
的printf(%d个,extend_matrix [K] [J]);
}
的printf(\\ n);
}
}INT主要(无效)
{
INT **矩阵;
INT ** extend_matrix;
INT行,列;
输出(输入COLS的行数:);
scanf函数(%I%I,&安培;行&安培; COL);
矩阵= create_matrix(行,列);
matrix_input(矩阵,行,列);
print_matrix(矩阵,行,列);
print_extend_matrix(extend_matrix,行,列);
残培();
返回0;
}
虽然@NPE建议你一个更好的办法。如果你想在分配内存extend_matrix()
错误在code(阅读评论的)
INT ** extend_matrix =的malloc(sizeof的为(int *)*行);
^在行
对于(K = 0; K<排排+; k ++)
^其中,作为环是排排+
{
extend_matrix [K] =的malloc(sizeof的(INT)* COL); //所以这导致错误,
//段故障
}
第二,你的观念是错误的复制存储:
extend_matrix =矩阵;
在这行要分配矩阵
到 extend_matrix
的错误。你需要在这里循环从矩阵[] []
每个元素复制到 extend_matrix [] []
。 (但首先纠正你的内存分配code 的)
I have a matrix dynamically allocated and I want to create another one which is the first matrix but with another copy beside. for example,I have the matrix:
11 22
My new matrix will be:
1 1 1 1 2 2 2 2
How can I concatenate them? This is my code in C:
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int **create_matrix(int row, int col)
{
int **matrix = malloc(sizeof (int*)*row);
int i;
for (i = 0; i < row; i++)
{
matrix[i] = malloc(sizeof (int)*col);
}
return matrix;
}
void matrix_input(int **matrix, int row, int col)
{
int i, j;
printf("enter the elements of the matrix:\n");
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
scanf("%d", &matrix[i][j]);
}
}
}
int **extend_matrix(int **matrix, int row, int col)
{
int k, j;
int i;
int **extend_matrix = malloc(sizeof (int*)*row);
for (k = 0; k < row + row; k++)
{
extend_matrix[k] = malloc(sizeof (int)*col);
}
extend_matrix = matrix;
extend_matrix = (int**) realloc(extend_matrix, (row + row) * sizeof (int*));
extend_matrix[j] = matrix[j];
for (i = 0; i < row; i++)
{
extend_matrix[k] = matrix[i];
}
}
void print_matrix(int **matrix, int row, int col)
{
int i, j;
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
printf(" %d ", matrix[i][j]);
}
printf("\n");
}
}
void print_extend_matrix(int **extend_matrix, int row, int col)
{
int k, j;
for (k = 0; k < row + row; k++)
{
for (j = 0; j < col; j++)
{
printf("%d", extend_matrix[k][j]);
}
printf("\n");
}
}
int main(void)
{
int **matrix;
int **extend_matrix;
int row, col;
printf("enter the number of rows of cols:");
scanf("%i%i", &row, &col);
matrix = create_matrix(row, col);
matrix_input(matrix, row, col);
print_matrix(matrix, row, col);
print_extend_matrix(extend_matrix, row, col);
getch();
return 0;
}
Although @NPE suggested to you a better way. If you want to allocate memory in extend_matrix()
error in your code (read comments)
int **extend_matrix = malloc(sizeof (int*)*row);
^ on row
for (k = 0; k < row + row; k++)
^ where as loop is for row + row
{
extend_matrix[k] = malloc(sizeof (int)*col); // So this cause an error,
// segment-fault
}
second, your concept is wrong to copy memory:
extend_matrix = matrix;
at this line you are assigning matrix
to extend_matrix
its wrong. you need loop here to copy each elements from matrix[][]
to extend_matrix[][]
. (but rectify your memory allocation code first)
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