在inline函数__LINE__行为 [英] Behavior of __LINE__ in inline functions

问题描述

我有传递行号和文件名，以一个错误处理的宏

I have a macro that passes the line number and file name to an error handler:

#define SYSTEM_FAILURE (error_code, comment) \
   System_Failure((error_code), (comment), __LINE__, __FILE__);

如何将 __ __ LINE 内联函数内使用时可以解决？

How will the __LINE__ be resolved when used inside an inlined function?

file.h:
inline int divide(int x, int y)
{
    if (y == 0)
    {
        SYSTEM_FAILURE(ENUM_DIVIDE_BY_ZERO, "divide by zero error");
    }
    return x/y;
}

威尔 __ LINE __ 包含头文件中的行号，或源文件的行数，其中内联函数被调用（假设编译器一个粘贴源$ C ​​$ C）？

Will __LINE__ contain the line number within the header file, or the line number of the source file where the inline function is called (assuming compiler does a "paste" in the source code)?

推荐答案

在C和C ++中，宏都没有（大部分）与实际code的任何知识评估和$ C之前被处理$ C（因此命名为preprocessor）。因此， __ FILE __ 将评估为file.h，而 __ LINE __ 将评估为对应于行的行号在其 SYSTEM_FAILURE 出现在file.h。

In C and C++, macros aren't (for the most part) evaluated with any knowledge of the actual code and are processed before the code (hence the name "preprocessor"). Therefore, __FILE__ would evaluate to "file.h", and __LINE__ would evaluate to the line number corresponding to the line on which SYSTEM_FAILURE appears in file.h.

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