C：用memset功能 [英] C: Using memset function

问题描述

这是code，我想尝试写：

This is the code that I want to try to write:

#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>
#include <malloc.h>

int main(int argc, char *argv[])
{
    float arry[3] = {0};

    memset(arry, (int) 10.0, 3*sizeof(float));

    return 0;
}

我的问题是，我想看看是否有可能使用的memset使数组中的每个条目比0。但是其他的一些，通过该行加强后，数组内容更改为极少数（ 0）。我不知道我在做什么错在这种情况下，与使用memset的（）函数。我希望这不是一个重复的职位，因为没有为我打字这似乎是建议相关的问题。

My problem is that I want to see if it's possible to use memset to make every entry of an array to be a number other than 0. However, After stepping through that line, the array contents change to a very small number (0). I wonder what I'm doing wrong in this case with using the memset() function. I hope this isn't a duplicate post, as none of the suggested related questions as I'm typing this appears to be.

推荐答案

铸造双为int只是创建二进制数00001010（10二进制），这是memset'ed值。因为它是一个字符，每个彩车是实际接收的位模式00001010 00001010 00001010 00001010。

Casting a double to an int just creates the binary number 00001010 (10 in binary), and that is the value that is memset'ed. Since it's a char, each of your floats is actually receiving the bit pattern 00001010 00001010 00001010 00001010.

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