如何采取空白的输入用C [英] How to Take whitespace in Input in C

问题描述

我想采取字符数组从控制台，它包括空格，我知道C中的唯一方法是scanf函数，但它错过停止服用输入一旦击中空白。我该怎么办？

下面是我在做什么。

 字符地址[100];scanf函数（％S，地址）;
 

解决方案

尝试使用与fgets（）。它会读取你选择的流的完整产品线（标准输入，我猜你正在寻找）。对于你的情况的一个例子：

 字符地址[100];与fgets（地址，100，标准输入）;
 

与fgets（）将至多读取第二个参数（负一）传递的字符数。没有缓冲区溢出，你会得到整个排队并包括一个换行符（或最多EOF）。注意，因为要读取的字符的最大数目是参数之一，它是可能的，你会得到一个局部线。检查是否返回的字符串中的最后一个字符的'\\ n'，你就会知道你有一个完整产品线。 EOF检测是pretty过于简单;一个 NULL 返回值和检查错误号应该帮助你。

感谢Chris（下同），关于部分行的地步。

I wanted to take character array from console and it also include white spaces, the only method i know in C is scanf, but it miss stop taking input once it hit with white space. What i should do?

Here is what i am doing.

char address[100];

scanf("%s", address);

解决方案

Try using fgets(). It will read a complete line from a stream of your choice (stdin, I guess you're looking for). An example for your case:

char address[100];

fgets(address, 100, stdin);

fgets() will read at most the number of characters passed in the second argument (minus one). No buffer overflow, and you'll get the whole line up to and including a newline character (or up to EOF). Note that since a maximum number of characters to read is one of the parameters, it is possible that you will get a partial line. Check to see if the last character in the returned string is '\n', and you'll know you got a complete line. EOF detection is pretty straightforward too; a NULL return value and a check to errno should help you out.

Thanks to Chris (below), for the point about partial lines.

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